CHIMNEYS AND DRAFT

The height and diameter of a properly designed chimney depend upon the

amount of fuel to be burned, its nature, the design of the flue, with

its arrangement relative to the boiler or boilers, and the altitude of

the plant above sea level. There are so many factors involved that as

yet there has been produced no formula which is satisfactory in taking

them all into consideration, and the methods used for determining stack

sizes are largely empirical. In this chapter a method sufficiently

comprehensive and accurate to cover all practical cases will be

developed and illustrated.

Draft is the difference in pressure available for producing a flow of

the gases. If the gases within a stack be heated, each cubic foot will

expand, and the weight of the expanded gas per cubic foot will be less

than that of a cubic foot of the cold air outside the chimney.

Therefore, the unit pressure at the stack base due to the weight of the

column of heated gas will be less than that due to a column of cold air.

This difference in pressure, like the difference in head of water, will

cause a flow of the gases into the base of the stack. In its passage to

the stack the cold air must pass through the furnace or furnaces of the

boilers connected to it, and it in turn becomes heated. This newly

heated gas will also rise in the stack and the action will be

continuous.

The intensity of the draft, or difference in pressure, is usually

measured in inches of water. Assuming an atmospheric temperature of 62

degrees Fahrenheit and the temperature of the gases in the chimney as

500 degrees Fahrenheit, and, neglecting for the moment the difference in

density between the chimney gases and the air, the difference between

the weights of the external air and the internal flue gases per cubic

foot is .0347 pound, obtained as follows:

Weight of a cubic foot of air at 62 degrees Fahrenheit = .0761 pound

Weight of a cubic foot of air at 500 degrees Fahrenheit = .0414 pound

------------------------

Difference = .0347 pound

Therefore, a chimney 100 feet high, assumed for the purpose of

illustration to be suspended in the air, would have a pressure exerted

on each square foot of its cross sectional area at its base of .0347 ×

100 = 3.47 pounds. As a cubic foot of water at 62 degrees Fahrenheit

weighs 62.32 pounds, an inch of water would exert a pressure of 62.32 ÷

12 = 5.193 pounds per square foot. The 100-foot stack would, therefore,

under the above temperature conditions, show a draft of 3.47 ÷ 5.193 or

approximately 0.67 inches of water.

The method best suited for determining the proper proportion of stacks

and flues is dependent upon the principle that if the cross sectional

area of the stack is sufficiently large for the volume of gases to be

handled, the intensity of the draft will depend directly upon the

height; therefore, the method of procedure is as follows:

1st. Select a stack of such height as will produce the draft required by

the particular character of the fuel and the amount to be burned per

square foot of grate surface.

2nd. Determine the cross sectional area necessary to handle the gases

without undue frictional losses.

The application of these rules follows:

Draft Formula--The force or intensity of the draft, not allowing for the

difference in the density of the air and of the flue gases, is given by

the formula:

/ 1 1 \

D = 0.52 H × P |--- - -----| (24)

\ T T_{1}/

in which

D = draft produced, measured in inches of water,

H = height of top of stack above grate bars in feet,

P = atmospheric pressure in pounds per square inch,

T = absolute atmospheric temperature,

T_{1} = absolute temperature of stack gases.

In this formula no account is taken of the density of the flue gases, it

being assumed that it is the same as that of air. Any error arising from

this assumption is negligible in practice as a factor of correction is

applied in using the formula to cover the difference between the

theoretical figures and those corresponding to actual operating

conditions.

The force of draft at sea level (which corresponds to an atmospheric

pressure of 14.7 pounds per square inch) produced by a chimney 100 feet

high with the temperature of the air at 60 degrees Fahrenheit and that

of the flue gases at 500 degrees Fahrenheit is,

/ 1 1 \

D = 0.52 × 100 × 14.7 | --- - --- | = 0.67

\ 521 961 /

Under the same temperature conditions this chimney at an atmospheric

pressure of 10 pounds per square inch (which corresponds to an altitude

of about 10,000 feet above sea level) would produce a draft of,

/ 1 1 \

D = 0.52 × 100 × 10 | --- - --- | = 0.45

\ 521 961 /

For use in applying this formula it is convenient to tabulate values of

the product

/ 1 1 \

0.52 × 14.7|--- - -----|

\ T T_{1}/

which we will call K, for various values of T_{1}. With these values

calculated for assumed atmospheric temperature and pressure (24) becomes

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