A, 87; B, 81; C, 78; D, 78; E, 65. A is paid 6, 9, 9, 22 points by B, C, D,
E respectively. B is paid 3, 3, 16 points by C, D, E respectively. C and D
are each paid 13 points by E. Thus A, B, C, D win 46, 16, 1, 1 points
respectively; and E loses 64.
Or we may proceed by adding all the scores together (making 389),
multiplying each player's score by 5 (the number of players), and paying
for the _differences_, above or below the total. If we multiply each
player's total, as given above, by 5, we get A, 435; B, 405; C and D, 390;
E, 325. The differences (by excess or defect) between these and 389 give
the same result as before.