But

$$ \delta(g^{\mu\nu} \Gamma^{\beta}_{\nu\alpha}) = - \frac{1}{2}

\delta \begin{bmatrix}g^{\mu\nu} & g^{\beta\lambda}\end{bmatrix}

(\frac{\partial g_{\nu\lambda}}{\partial x_{\alpha}} +

\frac{\partial g_{\alpha\lambda}}{\partial x_{\nu}} - \frac{\partial

g_{\alpha\nu}}{\partial x_{\lambda}}) $$

The terms arising out of the two last terms within the round bracket are

of different signs, and change into one another by the interchange of

the indices μ and β. They cancel each other in the expression for δH,

when they are multiplied by Γ_{μβ}^{α}, which is symmetrical with

respect to μ and β, so that only the first member of the bracket remains

for our consideration. Remembering (31), we thus have:—

δH = -Γ_{μβ}^{α} Γ_{να}^{β} δ_g_^{μν} + Γ_{μβ}^{α} δ_g__{α}^{μβ}

The Principle of Relativity · 第 146 / 203 题