5. Contra-variant and co-variant Four-vector.

Contra-variant Four-vector. The line-element is defined by the four

components _dx__{ν}, whose transformation law is expressed by the

equation

(5) $$ dx'_{\sigma} = \sum_{\nu} \frac{\partial x'_{\sigma}}{\partial

x_{\nu}} dx_{\nu} $$

The _dx′__{σ}’_s_ are expressed as linear and homogeneous function of

_dx__{ν}’_s_; we can look upon the differentials of the co-ordinates as

the components of a tensor, which we designate specially as a

contravariant Four-vector. Everything which is defined by Four

quantities A^{σ}, with reference to a co-ordinate system, and transforms

according to the same law,

(5a)

$$ A^{\sigma} = \sum_{\nu} \frac{\partial x'_{\sigma}}{\partial x_{\nu}}

A^{\nu} $$

we may call a contra-variant Four-vector. From (5. a), it follows at

once that the sums (A^{σ} ± B^{σ}) are also components of a four-vector,

when A^{σ} and B^{σ} are so; corresponding relations hold also for all

systems afterwards introduced as “tensors” (Rule of addition and

subtraction of Tensors).

_Co-variant Four-vector._

We call four quantities A_{ν} as the components of a covariant

four-vector, when for any choice of the contra-variant four vector B^{ν}

(6) ∑_{ν} A_{ν} B^{ν} = _Invariant_. From this definition follows the

law of transformation of the co-variant four-vectors. If we substitute

in the right hand side of the equation

∑_{σ} A′_{σ} B^{σ′} = ∑_{ν} A_{ν} B^{ν}.

the expressions

$$ \sum_{\sigma} \frac{\partial x_{\nu}}{\partial x_{\sigma'}}

B^{\sigma'} $$

for B^{ν} following from the inversion of the equation (5a) we get

$$ \sum_{\sigma} B^{\sigma'} \sum_{\nu} \frac{\partial x_{\nu}}{\partial

x_{\sigma'}} A_{\nu} = \sum_{\sigma} B^{\sigma'} A'_{\sigma} $$

As in the above equation B^{σ′} are independent of one another and

perfectly arbitrary, it follows that the transformation law is:—

$$ A'_{\sigma} = \sum \frac{\partial x_{\nu}}{\partial x_{\sigma'}}

A_{\nu} $$

_Remarks on the simplification of the mode of writing the expressions._

A glance at the equations of this paragraph will show that the indices

which appear twice within the sign of summation [for example ν in (5)]

are those over which the summation is to be made and that only over the

indices which appear twice. It is therefore possible, without loss of

clearness, to leave off the summation sign; so that we introduce the

rule: wherever the index in any term of an expression appears twice, it

is to be summed over all of them except when it is not expressedly said

to the contrary.

The difference between the co-variant and the contra-variant four-vector

lies in the transformation laws [(7) and (5)]. Both the quantities are

tensors according to the above general remarks; in it lies its

significance. In accordance with Ricci and Levi-civita, the

contravariants and co-variants are designated by the over and under

indices.

§ 6. Tensors of the second and higher ranks.

Contravariant tensor:—If we now calculate all the 16 products A^{μν} of

the components A^{μ} B^{ν}, of two contravariant four-vectors

(8) A^{μν} = A^{μ}B^{ν}

A^{μν}, will according to (8) and (5 a) satisfy the following

transformation law.

(9)

$$ A^{\sigma \tau'} = \frac{\partial x'_{\sigma}}{\partial x_{\mu}}

\frac{\partial x'_{\tau}}{\partial x_{\nu}} A^{\mu \nu} $$

We call a thing which, with reference to any reference system is defined

by 16 quantities and fulfils the transformation relation (9), a

contravariant tensor of the second rank. Not every such tensor can be

built from two four-vectors, (according to 8). But it is easy to show

that any 16 quantities A^{μν}, can be represented as the sum of

A^{μ}B^{ν} of properly chosen four pairs of four-vectors. From it, we

can prove in the simplest way all laws which hold true for the tensor of

the second rank defined through (9), by proving it only for the special

tensor of the type (8).

_Contravariant Tensor of any rank_:—It is clear that corresponding to

(8) and (9), we can define contravariant tensors of the 3rd and higher

ranks, with 4³, etc. components. Thus it is clear from (8) and (9) that

in this sense, we can look upon contravariant four-vectors, as

contravariant tensors of the first rank.

_Co-variant tensor._

If on the other hand, we take the 16 products A_{μν} of the components

of two co-variant four-vectors A_{μ} and B_{ν},

(10) A_{μν} = A_{μ} B_{ν}.

for them holds the transformation law

(11)

$$ A^{\sigma \tau'} = \frac{\partial x'_{\mu}}{\partial x_{\sigma'}}

\frac{\partial x'_{\nu}}{\partial x_{\tau'}} A^{\mu \nu} $$

By means of these transformation laws, the co-variant tensor of the

second rank is defined. All re-marks which we have already made

concerning the contravariant tensors, hold also for co-variant tensors.

_Remark_:—

It is convenient to treat the scalar Invariant either as a contravariant

or a co-variant tensor of zero rank.

_Mixed tensor._ We can also define a tensor of the second rank of the

type

(12) A_{μ}^{ν} = A_{μ}B^{ν}

which is co-variant with reference to μ and contravariant with reference

to ν. Its transformation law is

(13)

$$ A^{\tau'}_{\sigma} = \frac{\partial x_{\tau'}}{\partial x_{\beta}}

\frac{\partial \alpha}{\partial x_{\sigma'}} A^{\beta}_{\alpha} $$

Naturally there are mixed tensors with any number of co-variant indices,

and with any number of contra-variant indices. The co-variant and

contra-variant tensors can be looked upon as special cases of mixed

tensors.

_Symmetrical tensors_:—

A contravariant or a co-variant tensor of the second or higher rank is

called symmetrical when any two components obtained by the mutual

interchange of two indices are equal. The tensor A^{μν} or A_{μν} is

symmetrical, when we have for any combination of indices

(14) A^{μν} = A^{νμ}

or

(14a) A_{μν} = A_{νμ}.

It must be proved that a symmetry so defined is a property independent

of the system of reference. It follows in fact from (9) remembering (14)

$$ A^{\sigma \tau'} = \frac{\partial x_{\sigma'}}{\partial x_{\mu}}

\frac{\partial x'_{\tau}}{\partial x_{\nu}} A^{\mu \nu} = \frac{\partial

x_{\sigma'}}{\partial x_{\mu}} \frac{\partial x_{\tau'}}{\partial

x_{\nu}} A^{\nu \mu} = A^{\tau \sigma'} $$

_Antisymmetrical tensor._

A contravariant or co-variant tensor of the 2nd, 3rd or 4th rank is

called _antisymmetrical_ when the two components got by mutually

interchanging any two indices are equal and opposite. The tensor or

A^{μν} or A_{μν} is thus antisymmetrical when we have

(15) A^{μν} = -A^{νμ}

or

(15a) A_{μν} = -A_{νμ}.

Of the 16 components A^{μν}, the four components A^{μμ} vanish, the rest

are equal and opposite in pairs; so that there are only 6 numerically

different components present (Six-vector).

Thus we also see that the antisymmetrical tensor A^{μνσ} (3rd rank) has

only 4 components numerically different, and the antisymmetrical tensor

A^{μνστ} only one. Symmetrical tensors of ranks higher than the fourth,

do not exist in a continuum of 4 dimensions.

§ 7. Multiplication of Tensors.

_Outer multiplication of Tensors_:—We get from the components of a

tensor of rank _z_, and another of a rank _z′_, the components of a

tensor of rank (_z_ + _z′_) for which we multiply all the components of

the first with all the components of the second in pairs. For example,

we obtain the tensor Τ from the tensors A and B of different kinds:—

Τ_{μνσ} = A_{μν}B_{σ},

Τ^{αβγδ} = A^{αβ}B^{γδ},

Τ_{αβ}^{γδ} = A_{αβ}B^{γδ}.

The proof of the tensor character of Τ, follows immediately from the

expressions (8), (10) or (12), or the transformation equations (9),

(11), (13); equations (8), (10) and (12) are themselves examples of the

outer multiplication of tensors of the first rank.

_Reduction in rank of a mixed Tensor._

From every mixed tensor we can get a tensor which is two ranks lower,

when we put an index of co-variant character equal to an index of the

contravariant character and sum according to these indices (Reduction).

We get for example, out of the mixed tensor of the fourth rank

A_{αβ}^{γδ}, the mixed tensor of the second rank

The Principle of Relativity · 第 110 / 203 题