E = ½ mv² = (10⁶(0.9 × 3 × 10⁸)²)/2 = 3.6 × 10²² joules

The ship will use the same amount of energy to decelerate at its

destination. Note that this calculation assumes a perfect efficiency in

converting the energy of matter annihilation into the kinetic energy of

the space ship. The mass consumed is

m = E/c² = (3.6 × 10²²)/(9 × 10¹⁶) = 4.0 × 10⁵ kg

almost half the spaceship mass.

Direct Conversion of Energy · 第 62 / 65 题