HOW THE SCORE IS DEALT WITH.

The game is complete in one deal, and is won by the player who scores most

points, according to the foregoing table, exclusive of brisques. These

latter are only taken into account where the scores are otherwise equal.

If, after the addition of the brisques, the scores are still equal, the

game is drawn.

There is one other case in which the brisques are reckoned. The score of

1000 points is known as the "Rubicon," and a player not reaching this score

is "rubiconed." In this case, also, each player adds in his brisques; and

if the score of the loser is thereby brought up to 1000, he "saves the

rubicon."

Assuming that the rubicon is saved, the score of the loser is deducted from

that of the winner, fractions of a hundred being disregarded in both cases.

To the difference are added 500 points for game, and the total is the value

of the game, the stakes being usually so much per hundred points. If it

happen that the difference between the two scores is less than 100, it is

reckoned at that figure, making, with the 500 for game, 600. Thus, if the

respective scores are, A, 1510; B, 1240; A wins 1500 - 1200 + 500 = 800. If

A's score were 1550, and B's 1520, A would win 100 + 500 = 600.

If B is rubiconed, the value of the game is computed after a different

method. The points made by him (still disregarding fractions of a hundred)

instead of being subtracted from, are _added_ to the {22} score of the

winner, who is further entitled to 1000 for the game and 300 for

brisques.[12] Thus, if A has won 1320, and B 620, the value of A's game

will be 1300 + 600 + 1000 + 300 = 3200.

If the rubiconed player has scored less than 100, that amount (100) is

added to the score of the other player, as well as the 1000 for game and

300 for brisques, as before mentioned.

Hoyle's Games Modernized · 第 30 / 461 题