Consequently the discharge is

Q = x{½([Omega]0 + [Omega]_n) + [Omega]1 = [Omega]2 + ... + [Omega](n-1)}.

The areas [Omega]0, [Omega]1 ... are easily ascertained by means of

the polar planimeter. A slight difficulty arises in the part of the

solid lying above the last contour curve. This will have generally a

height which is not exactly x, and a form more rounded than the other

layers and less like a conical frustum. The volume of this may be

estimated separately, and taken to be the area of its base (the area

[Omega]_n) multiplied by 1/3 to ½ its height.

[Illustration: FIG. 151.]

Fig. 151 shows the results of one of Harlacher's gaugings worked out

in this way. The upper figure shows the section of the river and the

positions of the verticals at which the soundings and gaugings were

taken. The lower gives the curves of equal velocity, worked out from

the current meter observations, by the aid of vertical velocity

curves. The vertical scale in this figure is ten times as great as in

the other. The discharge calculated from the contour curves is 14.1087

cubic metres per second. In the lower figure some other interesting

curves are drawn. Thus, the uppermost dotted curve is the curve

through points at which the maximum velocity was found; it shows that

the maximum velocity was always a little below the surface, and at a

greater depth at the centre than at the sides. The next curve shows

the depth at which the mean velocity for each vertical was found. The

next is the curve of equal velocity corresponding to the mean velocity

of the stream; that is, it passes through points in the cross section

where the velocity was identical with the mean velocity of the stream.

Encyclopaedia Britannica, 11th Edition, "Husband" to "Hydrolysis" Volume 14, Slice 1 · 第 150 / 207 题