2,000 × 12
---------- = 12,000
2
square inches in which to be coiled. To satisfy the equation of
moments, _D_ must equal 3.5 _d_; hence, to satisfy both
these conditions
(¼)π[(3.5_d_)² - _d_²] = 12,000;
_d_ = 37 inches, or 3 feet 1 inch;
_D_ = 37 × 3.5 = 129.5 inches, or 10 feet 9½ inches.
The dimensions of the reel will then be: diameter of
hub 3 feet 1 inch; width between flanges, 8½ inches,
allowing ¼ inch on each side of the rope for clearance;
diameter of the flanges where they flare, 10 feet 9½
inches.