Adding a series of similar expressions, we find

_ x_n

/

| udx = h{1/2u_m + u_m+1 + u_m+2 + ... + u_n-1 + 1/2u_n} + [phi](x_n) - [phi](x_m).

_/x_m

The function [phi](x) can be expressed in terms either of differential

coefficients of u or of advancing or central differences; thus there

are three formulae.

(i.) The Euler-Maclaurin formula, properly so called, (due

independently to Euler and Maclaurin) is

_ x_n

/ 1 du_n 1 d^3u_n 1 d^5 u_n

| udx = h.[mu][sigma]u_n - -- h^2 ---- + --- h^4 ------ - ----- h^6 ------- + ...

_/x_m 12 dx 720 dx^3 30240 dx^5

B1 du_n B2 d^3u_n B3 d^5u_n

= h.[mu][sigma]u_n - -- h2 ---- + -- h^4 ------ - -- h^6 ------ + ...,

2! dx 4! dx^3 6! dx^5

where B1, B2, B3 ... are _Bernoulli's numbers_.

(ii.) If we express differential coefficients in terms of advancing

differences, we get a theorem which is due to Laplace:--

_ x_n

1 /

- | udx = [mu][sigma](u_n - u0) - 1/12 ([Delta]u_n - [Delta]u0) + 1/24 ( [Delta]^2u_n - [Delta]^2u0)

h _/x0

- 19/720 ([Delta]^3u_n - [Delta]^3u_0) + 3/160 ([Delta]^4 u_n - [Delta]^4 u0) - ...

Encyclopaedia Britannica, 11th Edition, "Diameter" to "Dinarchus" Volume 8, Slice 4 · 第 33 / 86 题