This gives the relation between [Delta] and D. Also we have

2q.2q - 1

u2 = u0 + 2qdPu0 + --------- dP^2u0 + ...

1.2

3q.3q - 1

u3 = u0 + 3qdPu0 + --------- dP^2u0 + ...

1.2

. .

. .

. .

and, if p is any integer,

p.p - 1

u_(p/q) = u0 + pdPu0 + ------- dP^2u0 + ....

1.2

From these equations up/q could be expressed in terms of u0, u1, u2,

...; this is a particular case of interpolation (q.v.).

18. _Differences and Differential Coefficients._--The various formulae

are most quickly obtained by symbolical methods; i.e. by dealing with

the operators [Delta], E, D, ... as if they were algebraical

quantities. Thus the relation E = e^(hD) (S 17) gives

hD = log_e (1 + [Delta]) = [Delta] - 1/2[Delta]^2 + 1/3 [Delta]^3 ...

/du\

or h( -- ) = [Delta]u0 - 1/2[Delta]^2u0 + 1/3 [Delta]^3u0 ....

\dx/0

The formulae connecting central differences with differential

coefficients are based on the relations [mu] = cosh 1/2hD = 1/2(e^1/2hD

+ e^ -1/2hD), [delta] = 2 sinh 1/2hD - e^ 1/2hD - e^ -1/2hD, and

may be grouped as follows:--

u0 = u0 \

|

[mu][delta]u0 = (hD + 1/6 h^3D^3 + 1/120 h^5 D^5 + ...)u0 |

|

[delta]^2u0 = (h^2D^2 + 1/12 h^4 D^4 + 1/360 h^6 D^6 + ...)u0 >

|

[mu][delta]^3u0 = (h^3D^3 + 1/4 h^5 D^5 + ...)u0 |

|

[delta]^4 u0 = (h^4 D^4 + 1/6 h^6 D^6 + ...)u0 /

. . .

. . .

. . .

[mu]u_1/2 = (1 + 1/8 h^2D^2 + 1/384 h^4 D^4 + 1/46080 h^6 D^6 + ...)u_1/2 \

|

[delta]u_1/2 = (hD + 1/24 h^3D^3 + 1/1920 h^5 D^5 + ...)u_1/2 |

|

[mu][delta]^2u_1/2 = (h^2D^2 + 5/24 h^4 D^4 + 91/5760 h^6 D^6 + ...)u_1/2 >

|

[delta]^3u_1/2 = (h^3D^3 + 1/8 h^5 D^5 + ...)u_1/2 |

|

[mu][delta]^4 u_1/2 = (h^4 D^4 + 7/24 h^6 D^6 + ...)u_1/2 /

. . .

. . .

. . .

u0 = u0 \

|

hDu0 = ([mu][delta] - 1/6 [mu][delta]^3 + 1/30 [mu][delta]^5 - ...)u0 |

|

h^2D^2u0 = ([delta]^2 - 1/12 [delta]^4 + 1/90 [delta]^6 - ...)u0 >

|

h^3D^3u0 = ([mu][delta]^3 1/4 [mu][delta]^5 + ...)u0 |

|

h^4 D^4 u_0 = ([delta]^4 - 1/6 [delta]^6 + ...)u0 /

. . .

. . .

. . .

u_1/2 = ([mu] - 1/8 [mu][delta]^2 + 3/128 [mu][delta]^4 - 5/1024 [mu][delta]^6 + ...)u_1/2 \

|

hDu_1/2 = ([delta] - 1/24 [delta]^3 + 3/640 [delta]^5 - ...)u_1/2 |

|

h^2D^2u_1/2 = ([mu][delta]^2 - 5/24 [mu][delta]^ + 259/5760 [mu][delta]^6 - ...)u_1/2 >

|

h^3D^3u_1/2 = ([delta]^3 - 1/8 [delta]^5 + ...)u_1/2 |

|

h^4 D^4 u_1/2 = ([mu][delta]^4 - 7/24 [mu][delta]^6 + ...)u_1/2 /

. . .

. . .

. . .

When u is a rational integral function of x, each of the above series

is a terminating series. In other cases the series will be an infinite

one, and may be divergent; but it may be used for purposes of

approximation up to a certain point, and there will be a "remainder,"

the limits of whose magnitude will be determinate.

19. _Sums and Integrals._--The relation between a sum and an integral

is usually expressed by the _Euler-Maclaurin formula_. The principle

of this formula is that, if um and um+1, are ordinates of a curve,

distant h from one another, then for a first approximation to the area

of the curve between um and um+1 we have 1/2h(u_m + u_m+1), and the

difference between this and the true value of the area can be

expressed as the difference of two expressions, one of which is a

function of x_m, and the other is the same function of x_m+1. Denoting

these by [phi](x_m) and [phi](xm+1), we have

_ x_m+1

/

| udx = 1/2h(u_m + u_m+1) + [phi](x_m+1 ) - [phi](x_m).

_/x_m

Encyclopaedia Britannica, 11th Edition, "Diameter" to "Dinarchus" Volume 8, Slice 4 · 第 32 / 86 题