Σ _R₁_² = _N_² (1² + 2² + &c. + _m_²)

_m_(_m_ + 1) (2_m_ +1)

= _N_² ———————————————————————

6

(_F₁_ + 2_F₂_ + &c. + _mFₘ_)

∴ _k_ = 6 ————————————————————————————— .

_Nm_(_m_ + 1) (2_m_ + 1)

In the case of Table III.

_m_ = 8, _N_ = 14,

_F₁_ + 2_F_ + 3_F₃_ + _mFₘ_ = 770·9;

whence _k_ = 0·27.

Thus the formula _F_ = 0·27 _R_ is deduced both by the method of least

squares, and by the method of graphical construction.

Experimental Mechanics A Course of Lectures Delivered at the Royal College of Science for Ireland · 第 163 / 171 题