TABLE III.

Let _k_ be the coefficient of friction. It is impossible to find any

value for _k_ which will satisfy the equation,

_F_ - _k R_ = 0,

for all the observed pairs of values of _F_ and _R_. We have then to

find the value for _k_ which, upon the whole, best represents the

experiments. _F_ - _k R_ is to be as near zero as possible for each

pair of values of _F_ and _R_.

In accordance with the principle of least squares, it is well known to

mathematicians, the best value of _k_ is that which makes

(_F₁_ - _k R₁_)² + (_F₂_ - _k R₂_)² + &c. + (_Fₘ_ - _k Rₘ_)²

a minimum where F₁ and R₁, F₂ and R₂ &c. are the simultaneous values of

F and R in the several experiments.

In fact, it is easy to see that, if this quantity be small, each of the

essentially positive elements,

(_F₁_ - _k R₁_)², &c.

of which it is composed, must be small also, and that therefore

_F_ - _k R_

must always be nearly zero.

Differentiating the sum of squares and equating the differential

coefficient to zero, we have according to the usual notation,

Σ _R₁_ (_F₁_ - _k R₁_) = 0;

Σ _R₁ F₁_

whence _k_ =  ————————————————.

Σ _R₁_²

The calculation of _k_ becomes simplified when (as is generally the

case in the tables) the loads _R₁_, _R₂_, &c., _Rₘ_ are of the form,

_N_, 2_N_, 3_N_ &c., _m N_.

In this case,

Σ _R₁_ _F₁_ = _N_ (_F₁_ + 2_F₂_ + 3_F₃_ + &c. + _mFₘ_).

Experimental Mechanics A Course of Lectures Delivered at the Royal College of Science for Ireland · 第 162 / 171 题