Substituting this value and that of d in formula (42)

/ 3.6 \ w^{2} L

p = 0.04839 K | 1 + ----- | ----------- (43)

\ d_{1} / D d_{1}^{5}

Some of the experimental determinations for the value of K are:

K = .005 for water (Unwin).

K = .005 for air (Arson).

K = .0028 for air (St. Gothard tunnel experiments).

K = .0026 for steam (Carpenter at Oriskany).

K = .0027 for steam (G. H. Babcock).

The value .0027 is apparently the most nearly correct, and substituting

in formula (43) gives,

/ 3.6 \ w^{2} L

p = 0.000131 | 1 + ---- | ----------- (44)

\ d_{1}/ D d_{1}^{5}

/ pDd_{1}^{5} \

w = 87 | -------------- |^{½} (45)

| / 3.6 \ |

| | 1 + ---- | L |

\ \ d_{1}/ /

Where w = the weight of steam passing in pounds per minute,

p = the difference in pressure between the two ends of the pipe in

pounds per square inch,

D = density of steam or weight per cubic foot,[80]

d_{1} = internal diameter of pipe in inches,

L = length of pipe in feet.

Steam, Its Generation and Use · 第 208 / 217 题