153 × 2 = 306 cubic feet of air per pound of carbon.

_Actual Volume_

_for One Pound Carbon_ _Per Cent_

_Cubic Feet_ _by Volume_

Carbon Dioxide 32 = 10.45 }

Oxygen 32 = 10.45 } = 20.91 per cent

Nitrogen 242 = 79.09

--- ------

306 = 100.00

In each case the volume of oxygen which combines with the carbon is

equal to (cubic feet of air × 20.91 per cent)--32 cubic feet.

It will be seen that no matter what the excess of air supplied, the

actual amount of carbon dioxide per pound of carbon remains the same,

while the percentage by volume decreases as the excess of air increases.

The actual volume of oxygen and the percentage by volume increases with

the excess of air, and the percentage of oxygen is, therefore, an

indication of the amount of excess air. In each case the sum of the

percentages of CO_{2} and O is the same, 20.9. Although the volume of

nitrogen increases with the excess of air, its percentage by volume

remains the same as it undergoes no change while combustion takes place;

its percentage for any amount of air excess, therefore, will be the same

after combustion as before, if cooled to the same temperature. It must

be borne in mind that the above conditions hold only for the perfect

combustion of a pound of pure carbon.

Carbon monoxide (CO) produced by the imperfect combustion of carbon,

will occupy twice the volume of the oxygen entering into its composition

and will increase the volume of the flue gases over that of the air

supplied for combustion in the proportion of

100 + ½ the per cent CO

1 to -----------------------

100

When pure carbon is the fuel, the sum of the percentages by volume of

carbon dioxide, oxygen and one-half of the carbon monoxide, must be in

the same ratio to the nitrogen in the flue gases as is the oxygen to the

nitrogen in the air supplied, that is, 20.91 to 79.09. When burning

coal, however, the percentage of nitrogen is obtained by subtracting the

sum of the percentages by volume of the other gases from 100. Thus if an

analysis shows 12.5 per cent CO_{2}, 6.5 per cent O, and 0.6 per cent

CO, the percentage of nitrogen which ordinarily is the only other

constituent of the gas which need be considered, is found as follows:

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