Find algebraically the real difference of latitude, meridional

difference of latitude and the difference of longitude. Reduce real

difference of latitude and difference of longitude to minutes. Take log

of the difference of longitude (Table 42) and add 10. From this log

subtract the log of difference of meridional parts. The result will be

the log tan of the True Course, which find in Table 44. On the same page

find the log sec of true course. Add to this the log of the real

difference of latitude, and if the result is more than 10, subtract 10.

This result will be the log of the distance sailed. This method should

be used only when steaming approximately a North and South course.

Note.--For detailed explanation of Tables 42 and 44 see Bowditch, pp.

271-276.

Assign for Night Reading Arts, in Bowditch:

183-184-185-186-187-188-189-194-259-260-261-262-263-264-265-266-267-268.

Also, one of the examples of Mercator sailing to be done by both the

Inspection and Logarithmic method.

SATURDAY LECTURE

GREAT CIRCLE SAILING--THE CHRONOMETER

In Tuesday's Lecture of this week, I explained how a Great Circle track

was laid down on one of the Great Circle Sailing Charts which are

prepared by the Hydrographic Office.

Supposing, however, you do not have these charts on hand. There is an

easy way to construct a great circle track yourself. Turn to Art. 194,

page 82, in Bowditch. Here is a table with an explanation as to how to

use it. Take, for instance, the same two points between which you just

drew a line on the great circle track. Find the center of this line and

the latitude of that point. At this point draw a line perpendicular to

the course to be sailed, the other end of which must intersect the

corresponding parallel of latitude given in the table. With this point

as the center of a circle, sweep an arc which will intersect the point

left and the point sought. This arc will be the great circle track to

follow.

To find the courses to be sailed, get the difference between the course

at starting and that at the middle of the circle, and find how many

quarter points are contained in it. Now divide the distance from the

starting point to the middle of the circle by the number of quarter

points. That will give the number of miles to sail on each quarter point

course. See this illustration:

[Illustration]

Difference between ENE and E = 2 pts. = 8 quarter points. Say distance

is 1600 miles measured by dividers or secured by Mercator Sailing

Method. Divide 1600 by 8 = 200. Every 200 miles you should change your

course 1/4 point East.

_The Chronometer_

The chronometer is nothing more than a very finely regulated clock. With

it we ascertain Greenwich Mean Time, i.e., the mean time at Greenwich

Observatory, England. Just what the words "Greenwich Mean Time" signify,

will be explained in more detail later on. What you should remember here

is that practically every method of finding your exact position at sea

is dependent upon knowing Greenwich Mean Time, and the only way to find

it is by means of the chronometer.

It is essential to keep the chronometer as quiet as possible. For that

reason, when you take an observation you will probably note the time by

your watch. Just before taking the observation, you will compare your

watch with the chronometer to notice the exact difference between the

two. When you take your observation, note the watch time, apply the

difference between the chronometer and watch, and the result will be the

CT.

For instance, suppose the chronometer read 3h 25m 10s, and your watch,

at the same instant, read 1h 10m 5s. C--W would be:

3h -- 25m -- 10s

-- 1 -- 10 -- 05

----------------

2h -- 15m -- 05s

Now suppose you took an observation which, according to your watch, was

at 2h 10m 05s. What would be the corresponding C T? It would be

WT 2h -- 10m -- 05s

C -- W 2 -- 15 -- 05

--------------------

CT 4h -- 25m -- 10s

If the chronometer time is less than the W T add 12 hours to the C T, so

that it will always be the larger and so that the amount to be added to

W T will always be +. For instance, CT 1h--25m--45s, WT 4h--13m--25s,

what is the C-W?

CT 13h--25m--45s

WT 4 --13 --25

----------------

C--W 9h--12m--20s

Now, suppose an observation was taken at 6h 13m 25s according to watch

time. What would be the corresponding CT?

WT 6h--13m--25s

C--W 9 --12 --20

----------------

15h--25m--45s

--12

----------------

CT 3h--25m--45s

Put in your Note-Book: CT = WT + C - W.

If, in finding C-W, C is less than W, add 12 hours to C, subtracting

same after CT is secured.

Example No. 1:

CT 3h--25m--10s

WT 1 --10 --05

----------------

C--W 2h--15m--05s

WT 2h--10m--05s

+ C--W 2 --15 --05

----------------

CT 4h--25m--10s

Example No. 2:

CT 1h--25m--45s

WT 4h--13m--25s

(+12 hrs.) CT 13h--25m--45s

WT 4 --13 --25

----------------

C-W 9h--12m--20s

WT 6h--13m--25s

+ C-W 9 --12 --20

----------------

15h--25m--45s

(-12 hrs.) 12

----------------

CT 3h--25m--45s

There is one more very important fact to know about the chronometer. It

is physically impossible to keep it absolutely accurate over a long

period of time. Instead of continually fussing with its adjustment and

hands, the daily rate of error is ascertained, and from this the exact

time for any given day. It is an invariable practice among good mariners

to _leave the chronometer alone_. When you are in port, you can find out

from a time ball or from some chronometer maker what your error is. With

this in mind, you can apply the new correction from day to day. Here is

an example (Put in your Note-Book):

On June 1st, CT 7h--20m--15s, CC 2m--40s fast. On June 16th, (same CT)

CC 1m--30s fast. What was the corresponding G.M.T. on June 10th?

June 1st 2m--40s fast

16th 1m--30s fast

----------------

1m--10s

60

--

60

10

--

15) 70s (4.6 sec. Daily Rate of error losing

June 1st-10th, 9 days times 4.6 sec. = 41 sec. losing

June 1st 2m--40s fast

June 10th 41s losing

---------

June 10th 1m--59s fast

CT 7h--20m--15s

CC -- 1 --59

------------

G.M.T. 7h--18m--16s on June 10th

If CC is fast, subtract from CT

If CC is slow, add to CT

WEEK III--CELESTIAL NAVIGATION

TUESDAY LECTURE

CELESTIAL CO-ORDINATES, EQUINOCTIAL SYSTEM, ETC.

We have already discussed the way in which the earth is divided so as to

aid us in finding our position at sea, i.e., with an equator, parallels

of latitude, meridians of longitude starting at the Greenwich meridian,

etc. We now take up the way in which the celestial sphere is

correspondingly divided and also simple explanations of some of the more

important terms used in Celestial Navigation.

As you stand on any point of the earth and look up, the heavenly bodies

appear as though they were situated upon the surface of a vast hollow

sphere, of which your eye is the center. Of course this apparent concave

vault has no existence and we cannot accurately measure the distance of

the heavenly bodies from us or from each other. We can, however, measure

the direction of some of these bodies and that information is of

tremendous value to us in helping us to fix our position.

Now we could use our eye as the center of the celestial sphere but more

accurate than that is to use the center of the earth. Suppose we do use

the center of the earth as the place from which to observe these

celestial bodies and, in imagination, transfer our eye there. Then we

will find projected on the celestial sphere not only the heavenly bodies

but the imaginary points and circles of the earth's surface. Parallels

of latitude, meridians of longitude, the equator, etc., will have the

same imaginary position on the celestial sphere that they have on the

earth. Your actual position on the earth will be projected in a point

called your zenith, i.e., the point directly overhead.

[Illustration]

From this we get the definition that the Zenith of an observer on the

earth's surface is the point in the celestial sphere directly overhead.

It would be a simple matter to fix your position if your position never

changed. But it is always changing with relation to these celestial

bodies. First, the earth is revolving on its own axis. Second, the

earth is moving in an elliptic track around the sun, and third, certain

celestial bodies themselves are moving in a track of their own. The

changes produced by the daily rotation of the earth on its axis are

different for observers at different points on the earth and, therefore,

depend upon the latitude and longitude of the observer. But the changes

arising from the earth's motion in its orbit and the motion of various

celestial bodies in their orbits, are true no matter on what point of

the earth you happen to be. These changes, therefore, in their relation

to the center of the earth, may be accurately gauged at any instant. To

this end the facts necessary for any calculation have been collected and

are available in the Nautical Almanac, which we will take up in more

detail later.

Now with these facts in mind, let us explain in simple words the meaning

of some of the terms you will have to become acquainted with in

Celestial Navigation.

In the illustration (Bowditch p. 88) the earth is supposed to be

projected upon the celestial sphere N E S W. The Zenith of the observer

is projected at Z and the pole of the earth which is above the horizon

is projected at P. The other pole is not given.

The Celestial Equator is marked here E Q W and like all other points and

lines previously mentioned, it is the projection of the Equator until it

intersects the celestial sphere. Another name for the Celestial Equator

is the Equinoctial.

All celestial meridians of longitude corresponding to longitude

meridians on the earth are perpendicular to the equinoctial and likewise

P S, the meridian of the observer, since it passes through the

observer's zenith at Z, is formed by the extension of the earth's

meridian of the observer and hence intersects the horizon at its N and S

points. This makes clear again just what is the meridian of the

observer. It is the meridian of longitude which passes through the N and

S poles and the observer's zenith. In other words, when the sun or any

other heavenly body is on your meridian, a line stretched due N and S,

intersecting the N and S poles, will pass through your zenith and the

center of the sun or other celestial body. To understand this is

important, for no sight with the sextant is of value except with

relation to your meridian.

The Declination of any point in the celestial sphere is its distance in

arc, North or South of the celestial equator, i.e., N or S of the

Equinoctial.

North declinations, i.e., declinations north of the equinoctial are

always marked, +; those south of the equinoctial, -. For instance, in

the Nautical Almanac, you will never see a declination of the sun or

other celestial body marked, N 18 deg. 28' 30". It will always be marked

+18 deg. 28' 30" and a south declination will be marked -18 deg. 28' 30".

Another fact to remember is that Declination on the celestial sphere

corresponds to latitude on the earth. If, for instance, the Sun's

declination is +18 deg. 28' 30" at noon, Greenwich, then at that instant,

i.e., noon at Greenwich, the sun will be directly overhead a point on

earth which is in latitude N 18 deg. 28' 30".

The Polar Distance of any point is its distance in arc from either pole.

It must, therefore, equal 90 deg. minus the declination, if measured from

the pole of the same name as the declination or 90 deg. plus the declination

if measured from the pole of the opposite name.

P M is the polar distance of M from P, or P B the polar distance of B

from P.

The true altitude of a celestial body is its angular height from the

true horizon.

The zenith distance of any point or celestial body is its angular

distance from the zenith of the observer.

The Ecliptic is the great circle representing the path in which the sun

appears to move in the celestial sphere. As a matter of fact, you know

that the earth moves around the sun, but as you observe the sun from

some spot on the earth, it appears to move around the earth. This

apparent track is called the Ecliptic as stated before, and in the

illustration the Ecliptic is represented by the curved line, C V T. The

plane of the Ecliptic is inclined to that of the Equinoctial at an angle

of 23 deg. 27-1/2', and this inclination is called the obliquity of the

Ecliptic.

The Equinoxes are those points at which the Ecliptic and Equinoctial

intersect, and when the sun occupies either of these two positions, the

days and nights are of equal length. The Vernal Equinox is that one

which the sun passes through or intersects in going from S to N

declination, and the Autumnal Equinox that which it passes through or

intersects in going from N to S declination. The Vernal Equinox (V in

the illustration) is also designated as the First Point of Aries which

is of use in reckoning star time and will be mentioned in more detail

later.

The Solstitial Points, or Solstices, are points of the Ecliptic at a

distance of 90 deg. from the Equinoxes, at which the sun attains its highest

declination in each hemisphere. They are called the Summer and Winter

Solstice according to the season in which the sun appears to pass these

points in its path.

To sum up: The way to find any point on the earth is to find the

distance of this point N or S of the equator (i.e., its Latitude) and

its distance E or W of the meridian at Greenwich (i.e., its longitude).

In the celestial sphere, the way to find the location of a point or

celestial body such as the sun is to find its declination (i.e.,

distance in arc N or S of the equator) and its hour angle. By hour

angle, I mean the distance in time from your meridian to the meridian of

the point or celestial body in question.

Assign for Night reading, Arts, in Bowditch:

270-271-272-273-274-275-277-278-279-280-282-283-284.

WEDNESDAY LECTURE

TIME BY THE SUN--MEAN TIME, SOLAR TIME, CONVERSION, ETC.

There is nothing more important in all Navigation than the subject of

Time. Every calculation for determining the position of your ship at sea

must take into consideration some kind of time. Put in your Note-Book:

There are three kinds of time:

1. Apparent or solar time, i.e., time by the sun.

2. Mean Time, i.e., clock time.

3. Sidereal Time, or time by the stars.

So far as this lecture is concerned, we will omit any mention of

sidereal time, i.e., time by the stars. We will devote this morning to

sun time, i.e., apparent time, and mean time.

Apparent or Solar Time is, as stated before, nothing more than sun time

or time by the sun. The hour angle of the center of the sun is the

measure of apparent or solar time. An apparent or solar day is the

interval of time it takes for the earth to revolve completely around on

its axis every 24 hours. It is apparent noon at the place where you are

when the center of the sun is directly on your meridian, i.e., on the

meridian of longitude which runs through the North and South poles and

also intersects your zenith. This is the most natural and the most

accurate measure of time for the navigator at sea and the unit of time

adopted by the mariner is the apparent solar day. Apparent noon is the

time when the latitude of your position can be most easily and most

exactly determined and on the latitude by observation just secured we

can get data which will be of great value to us for longitude sights

taken later in the day.

Now it would be very easy for the mariner if he could measure apparent

time directly so that his clock or other instrument would always tell

him just what the sun time was. It is impossible, however, to do this

because the earth does not revolve at a uniform rate of speed.

Consequently the sun is sometimes a little ahead and sometimes a little

behind any average time. You cannot manufacture a clock which will run

that way because the hours of a clock must be all of exactly the same

length and it must make noon at precisely 12 o'clock every day. Hence we

distinguish clock time from sun time by calling clock time, mean (or

average) time and sun time, apparent or solar time. From this

explanation you are ready to understand such expressions as Local Mean

Time, which, in untechnical language, signifies clock time at the place

where you are; Greenwich Mean Time which signifies clock time at

Greenwich; Local Apparent Time, which signifies sun time at the place

where you are; Greenwich Apparent Time, which signifies sun time at

Greenwich.

Now the difference between apparent time and mean time can be found for

any minute of the day by reference to the Nautical Almanac which we will

take up later in more detail. This difference is called the Equation of

Time.

There is one more fact to remember in regard to apparent and mean time.

It is the relation of the sun's hour angle to apparent time. In the

first place, what is a definition of the sun's HA? It is the angle at

the celestial pole between the meridian intersecting any given point and

the meridian intersecting the center of the sun. It is measured by the

arc of the celestial equator intersected between the meridian of any

point and the meridian intersecting the center of the sun.

[Illustration]

For instance, in the above diagram, suppose PG is the meridian at

Greenwich, and PS the meridian intersecting the sun. Then the angle at

the pole GPS, measured by the arc GS would be the Hour Angle of

Greenwich, or the Greenwich Hour Angle. And now you notice that this

angular measure is exactly the same as apparent time at Greenwich or

Greenwich Apparent Time, for Greenwich Apparent Time is nothing more

than the distance in time Greenwich, England, or the meridian at

Greenwich is from the sun, i.e., the time it takes the earth to revolve

from Greenwich to the sun; and that distance is exactly measured by the

Greenwich Hour Angle or the arc on the celestial equator, GS.

The same is correspondingly true of Local Apparent Time and the ship's

Hour Angle. Suppose, for instance, PL is the meridian intersecting the

place where your ship is. Then your ship's hour angle would be the angle

at the pole intersecting the meridian of your ship and the meridian of

the sun or LPS and measured by the arc LS. And you will note that this

distance is exactly the same as apparent time at the ship, for Apparent

Time at ship is nothing more than the distance in time which the ship is

from the sun. We can sum up all this information in a few simple rules,

which put in your Note-Book:

Mean Time = Clock Time.

G.M.T. = Greenwich Mean Time.

L.M.T. = Local Mean Time.

Apparent Time = Actual or Sun Time.

G.A.T. (G.H.A.) = Greenwich Apparent Time or Greenwich Hour Angle.

L.A.T. (S.H.A.) = Local Apparent Time or Ship's Hour Angle.

Difference between apparent and mean time or mean and apparent

time--Equation of Time.

Right under this in your Note-Book put the following diagram, which I

will explain:

[Illustration]

You will see from this diagram that civil time commences at midnight and

runs through 12 hours to noon. It then commences again and runs through

12 hours to midnight. The Civil Day, then, is from midnight to midnight,

divided into two periods of 12 hours each.

The astronomical day commences at noon of the civil day of the same

date. It comprises 24 hours, reckoned from O to 24, from noon of one day

to noon of the next. Astronomical time, either apparent or mean, is the

hour angle of the true or mean sun respectively, measured to the

westward throughout its entire daily circuit.

Since the civil day begins 12 hours before the astronomical day and ends

12 hours before it, A.M. of a new civil day is P.M. of the astronomical

day preceding. For instance, 6 hours A.M., April 15th civil time is

equivalent to 18 hours April 14th, astronomical time.

Now, all astronomical calculations in which time is a necessary fact to

be known, must be expressed in astronomical time. As chronometers have

their face marked only from 0 to 12 as in the case of an ordinary watch,

it is necessary to transpose this watch or chronometer time into

astronomical time. No transposing is necessary if the time is P.M., as

you can see from the diagram that both civil and astronomical times up

to 12 P.M. are the same. But in A.M. time, such transposing is

necessary. Put in your Note-Book:

Whenever local or chronometer time is A.M., deduct 12 hours from such

time to get the correct astronomical time:

CT 15d-- 9h--10m--30s A.M.

--12

------------------------

CT 14d--21h--10m--30s

------

L.M.T. 10d-- 4h--40m--16s A.M.

--12

------------------------

L.M.T. 9d--16h--40m--16s

Now we come to a very important application of time. You will remember

that in one of the former lectures we stated that to find our latitude,

we had to find how far North or South of the equator we were, and to

find our longitude, we had to find how far East or West of the meridian

at Greenwich we were. Never mind about latitude for the present. We can

find our longitude exactly if we know our Greenwich time and our time at

ship. For instance, in the accompanying diagram:

[Illustration]

Suppose PG is the meridian at Greenwich, then anything to the west of PG

is West longitude and anything to the East of PG is East longitude. Now

suppose GPS is the H.A. of G. or G.A.T.--i.e., the distance in time G.

is from the sun. And L P S is the H.A. of the ship or L.A.T.--i.e., the

distance in time the ship is from the sun. Then the difference between G

P S and L P S is G P L, measured by the arc L G, and that is the

difference that the ship, represented by its meridian PL, is from the

Greenwich meridian PG. In other words, that is the ship's longitude for,

as mentioned before, longitude is the distance East or West of Greenwich

that any point is, measured on the arc of the celestial equator. The

longitude is West, for you can see LPG or the arc LG is west of the

meridian PG.

Likewise if P E is the meridian of your ship, the Longitude in time is

the S.H.A. or L.A.T., E P S (the distance your ship is from the sun)

less the G.H.A. or G.A.T., G P S (the distance Greenwich is from the

sun) which is the angle G P E measured by the arc G E. And this

Longitude is East for you can see G P E, measured by G E, is east of the

Greenwich meridian, P G.

In both these cases, however, the longitude is expressed in time, i.e.,

so many hours, minutes and seconds from the Greenwich meridian and we

wish to express this distance in degrees, minutes and seconds of arc.

The earth describes a circle of 360 deg. every 24 hours. Then if you are 1

hour from Greenwich, you are 1/24 of 360 deg. or 15 deg. from Greenwich and if

you are 12 hours from Greenwich, you are 1/2 of 360 deg. or 180 deg. from

Greenwich. By keeping this in mind, you should be able to transpose time

into degrees, minutes and seconds of arc for any fraction of time. It

is, however, all worked out in Table 7 of Bowditch which turn to. (Note

to Instructor: Explain this table carefully). Put in your Note-Book:

89 deg. 24' 26" = (89 deg.) 5h--56m

(24') 1m--36s

(26") 1--44/60s

--------------------

5h--57m--37s 44/60s = 38s

4h--42m--26s

4h--40m = 70 deg.

2m--24s = 36'

2s = 30"

-----------

70 deg. 36' 30"

Also put in your Note-Book this diagram and these formulas: (For diagram

use illustration on p. 40.)

L.M.T. + West Lo. = G.M.T. L.A.T. + West Lo. = G.A.T.

L.M.T. - East Lo. = G.M.T. L.A.T. - East Lo. = G.A.T.

G.M.T. - West Lo. = L.M.T. G.A.T. - West Lo. = L.A.T.

G.M.T. + East Lo. = L.M.T. G.A.T. + East Lo. = L.A.T.

If G.M.T. or G.A.T. is greater than L.M.T. or L.A.T. respectively, Lo.

is West.

If G.M.T. or G.A.T. is less than L.M.T. or L.A.T. respectively, Lo. is

East.

Example:

In longitude 81 deg. 15' W, L.M.T. is April 15d--10h--17m--30s A.M. What is

G.M.T.?

L.M.T. 15d--10h--17m--30s A.M.

--12

------------------

L.M.T. 14d--22h--17m--30s

5 --25 W +

------------------

G.M.T. 15d-- 3h--42m--30s

--------

G.M.T. April 15d-- 3h--42m--30s

L.M.T. April 15d--10h--17m--30s A.M.

In what Lo. is ship?

G.M.T. 15d 3h--42m--30s

L.M.T. 14d 22h--17m--30s

------------------

Lo. in T 5h--25m--00s W

Lo. = 81 deg. 15'W

Assign also for Night Work reading the following articles in Bowditch:

276-278-279-226-228-286-287-288-290-291-294 (omitting everything on page

114.)

THURSDAY LECTURE

SIDEREAL TIME--RIGHT ASCENSION

Our last lecture was devoted to a discussion of sun time. Today we are

going to talk about star time, or, using the more common words, sidereal

time.

Now, just one word of review. You remember that we have learned that

astronomical time is reckoned from noon of one day to noon of the next

and hence the astronomical day corresponds to the 24 hours of a ship's

run. The hours are counted from 0 to 24, so that 10 o'clock in the

morning of October 25th is astronomically October 24th, 22 hours or 22

o'clock of October 24th.

Lectures in Navigation · 第 3 / 9 段