Hence equations (1) and (2) become

_c_ curl H = ∂D/∂_t_ + _u_ div D + curl Vect. [D_u_] + ρν (1·1)

and

-_c_ curl E = ∂B/∂_t_ + _u_ div B + curl Vect. [B_u_] (2·1)

which gives finally, for ρ = 0 and div B = 0,

∂D/∂_t_ + _u_ div D = _c_ curl (H - 1/_c_ Vect. [D_u_]) (1·2)

∂B/∂_t_ = -_c_ curl (E - 1/_c_ Vect. [_u_B]) (2·2)

Let us consider a beam travelling along the _x_-axis, with apparent

velocity _v_ (_i.e._, velocity with respect to the fixed ether) in

medium moving with velocity _u__{_x_} = _u_ in the same direction.

Then if the electric and magnetic vectors are proportional to

_e_^{_i_A(_x_ - _vt_)}, we have

∂/∂_x_ = _i_A, ∂/∂_t_ = -_i_A_v_, ∂/∂_y_ = ∂/∂_z_ = 0, _u__{_y_} =

_u__{_z_} = 0

The Principle of Relativity · 第 186 / 203 题