So we get by the substitution of δω in (20a), remembering that

δ(_dx__{ν}/_d_λ) = (_d_/_d_λ)(δ_x__{ν})

after partial integration,

{ λ₃

{ ∫ _d_λ _k__{σ} δ_x__{σ} = 0

(20b) { λ₁

{

{ where _k__{σ} = (_d_/_d_λ){(_g__{μν}/ω) · (_dx__{μ}/_d_λ)}

- (1/(2ω))(∂_g__{μν}/∂_x__{σ}

× (_dx__{μ}/_d_λ) · (_dx__{ν}/_d_λ).

From which it follows, since the choice of δν_{σ} is perfectly arbitrary

that _k__{σ}_’s_ should vanish. Then

(20c) _k__{σ} = 0 (σ = 1, 2, 3, 4)

are the equations of geodetic line; since along the geodetic line

considered we have _ds_ ≠ 0, we can choose the parameter λ, as the

length of the arc measured along the geodetic line. Then _w_ = 1, and we

would get in place of (20c)

$$ g_{\mu\nu} \frac{\partial^2 x_{\mu}}{\partial s^2} + \frac{\partial

g_{\mu\nu}}{\partial x_{\sigma}} \frac{\partial x_{\sigma}}{\partial s}

\frac{\partial x_{\mu}}{\partial s} - \frac{1}{2} \frac{\partial

g_{\mu\sigma}}{\partial x_{\nu}} \frac{\partial x_{\mu}}{\partial s}

\frac{\partial x_{\sigma}}{\partial s} = 0 $$

Or by merely changing the notation suitably,

(20d) $$ g_{\alpha\sigma} \frac{d^2 x_{\alpha}}{ds^2} +

\begin{bmatrix}\mu\nu\\\sigma\end{bmatrix} \frac{dx_{\mu}}{ds}

\frac{dx_{\nu}}{ds} = 0 $$

where we have put, following Christoffel,

(21)

$$ \begin{bmatrix}\mu\nu\\\sigma\end{bmatrix} = \frac{1}{2}

\begin{bmatrix}\frac{\partial g_{\mu\sigma}}{\partial x_{\nu}} +

\frac{\partial g_{\nu\sigma}}{\partial x_{\mu}} - \frac{\partial

g_{\mu\nu}}{\partial \sigma}\end{bmatrix} $$

Multiply finally (20d) with _g_^{στ} (outer multiplication with

reference to τ, and inner with respect to σ) we get at last the final

form of the equation of the geodetic line—

$$ \frac{d^2 x_{\tau}}{ds^2} + \begin{Bmatrix}\mu\nu\\\tau\end{Bmatrix}

\frac{dx_{\mu}}{ds} \frac{dx_{\nu}}{ds} = 0 $$

Here we have put, following Christoffel,

$$ \begin{Bmatrix}\mu\nu\\\tau\end{Bmatrix} = g^{\tau\alpha}

\begin{bmatrix}\mu\nu\\\alpha\end{bmatrix} $$

§ 10. Formation of Tensors through Differentiation.

Relying on the equation of the geodetic line, we can now easily deduce

laws according to which new tensors can be formed from given tensors by

differentiation. For this purpose, we would first establish the general

co-variant differential equations. We achieve this through a repeated

application of the following simple law. If a certain curve be given in

our continuum whose points are characterised by the arc-distances _s_,

measured from a fixed point on the curve, and if further φ, be an

invariant space function, then _d_φ/_ds_ is also an invariant. The proof

follows from the fact that _d_φ as well as _ds_, are both invariants

The Principle of Relativity · 第 131 / 203 题