1:(√(1 - v²/_c²_)) in length, in the direction of its motion

_l_/_l′_ = 1/√(1 - _v²_/_c²_) _l′_ = _l_(1 - _v²_/_c²_).

This hypothesis sounds rather phantastical. For the contraction is not

to be thought of as a consequence of the resistance of ether, but purely

as a gift from the skies, as a sort of condition always accompanying a

state of motion.

I shall show in our figure that Lorentz’s hypothesis is fully equivalent

to the new conceptions about time and space. Thereby it may appear more

intelligible. Let us now, for the sake of simplicity, neglect (_y_, _z_)

and fix our attention on a two dimensional world, in which let upright

strips parallel to the _t_-axis represent a state of rest and another

parallel strip inclined to the _t_-axis represent a state of uniform

motion for a body, which has a constant spatial extension (see fig. 1).

If OA′ is parallel to the second strip, we can take _t′_ as the _t_-axis

and _x′_ as the _x_-axis, then the second body will appear to be at

rest, and the first body in uniform motion. We shall now assume that the

first body supposed to be at rest, has the length _l_, _i.e._, the cross

section PP of the first strip upon the _x_-axis = _l_^. OC, where OC is

the unit measuring rod upon the _x_-axis—and the second body also, when

supposed to be at rest, has the same length _l_, this means that, the

cross section Q′Q′ of the second strip has a cross-section _l_^· OC′,

when measured parallel to the _x′_-axis. In these two bodies, we have

now images of two Lorentz-electrons, one of which is at rest and the

other moves uniformly. Now if we stick to our original coordinates, then

the extension of the second electron is given by the cross section QQ of

the strip belonging to it measured parallel to the _x_-axis. Now it is

clear since Q′Q′ = _l_^· OC′, that QQ = _l_^· OD′.

The Principle of Relativity · 第 103 / 203 题