If Φ = 0, we have the simple formula:—

$$ \frac {E'}{E} = (\frac{1 - \frac{v}{c}}{1 +

\frac{v}{c}})^{\frac{1}{2}} $$

It is to be noticed that the energy and the frequency of a light-complex

vary according to the same law with the state of motion of the observer.

Let there be a perfectly reflecting mirror at the co-ordinate-plane ξ =

0, from which the plane-wave considered in the last paragraph is

reflected. Let us now ask ourselves about the light-pressure exerted on

the reflecting surface and the direction, frequency, intensity of the

light after reflexion.

Let the incident light be defined by the magnitudes A cos Φ, _v_

(referred to the system K). Regarded from _k_, we have the corresponding

magnitudes:

$$ A' = A \frac{1 - \frac{v}{c} \cos \Phi}{\sqrt{1 - \frac{v^2}{c^2}}}

$$

$$ \cos \Phi' = \frac{\cos \Phi - \frac{v}{c}}{1 - \frac{v}{c} \cos

\Phi} $$

$$ \nu' = \nu \frac{1 - \frac{v}{c} \cos \Phi}{\sqrt{1 -

\frac{v^2}{c^2}}} $$

For the reflected light we obtain, when the process is referred to the

system _k_:—

The Principle of Relativity · 第 31 / 203 题