If for _x′_, we substitute its value _x_ - _tv_, we obtain

_v_._c_

τ = φ (_v_). β (_t_ - ----------- ,

c²

ξ = φ (_v_). β (_x_ - _vt_) ,

η = φ (_v_) _y_

ζ = φ (_v_) _z_ ,

where

$$ \beta = \frac {1}{\sqrt {1 - \frac {v^2}{c^2}}} $$

and

φ (_v_) = _ac_ / √ (_c²_ - _v²_) = _a_ / β

is a function of _v_.

If we make no assumption about the initial position of the moving system

and about the null-point of _t_, then an additive constant is to be

added to the right hand side.

We have now to show, that every ray of light moves in the moving system

with a velocity _c_ (when measured in the moving system), in case, as we

have actually assumed, _c_ is also the velocity in the stationary

system; for we have not as yet adduced any proof in support of the

assumption that the principle of relativity is reconcilable with the

principle of constant light-velocity.

At a time τ = _t_ = 0 let a spherical wave be sent out from the common

origin of the two systems of co-ordinates, and let it spread with a

velocity _c_ in the system K. If (_x_, _y_, _z_), be a point reached by

the wave, we have

_x²_ + _y²_ + _z²_ = _c²__t²_

with the aid of our transformation-equations, let us transform this

equation, and we obtain by a simple calculation,

ξ² + η² + ζ² = _c²_τ².

Therefore the wave is propagated in the moving system with the same

velocity _c_, and as a spherical wave.[7] Therefore we show that the two

principles are mutually reconcilable.

In the transformations we have got an undetermined function φ(_v_), and

we now proceed to find it out.

Let us introduce for this purpose a third co-ordinate system _k′_, which

is set in motion relative to the system _k_, the motion being parallel

to the ξ-axis. Let the velocity of the origin be (-_v_). At the time _t_

= 0, all the initial co-ordinate points coincide, and for _t_ = _x_ =

_y_ = _z_ = 0, the time _t′_ of the system _k′_ = 0. We shall say that

(_x′_ _y′_ _z′_ _t′_) are the co-ordinates measured in the system _k′_,

then by a two-fold application of the transformation-equations, we

obtain

_v_

τ′ = φ(-_v_)β(-_v_){τ + ----- ξ}

_c²_

= φ(_v_)φ(-_v_)t,

_x′_ = φ](_v_)β(_v_)(ξ + _v_τ)

= φ(_v_)φ(-_v_)_x_, etc.

Since the relations between (_x′_, _y′_, _z′_, _t′_), and (_x_, _y_,

_z_, _t_) do not contain time explicitly, therefore K and _k′_ are

relatively at rest.

It appears that the systems K and _k′_ are identical.

∴ φ(_v_)φ(-_v_) = 1.

Let us now turn our attention to the part of the ξ-axis between (ξ = 0,

η = 0, ζ = 0), and (ξ = 0, η = 1, ζ = 0). Let this piece of the _y_-axis

be covered with a rod moving with the velocity _v_ relative to the

system K and perpendicular to its axis;—the ends of the rod having

therefore the co-ordinates

_x₁_ = _vt_, _y₁_ = _l_ / φ(_v_), _z₁_ = 0

_x₂_ = _vt_, _y₂_ = 0, _z₂_ = 0

Therefore the length of the rod measured in the system K is _l_/φ(_v_).

For the system moving with velocity (-_v_), we have on grounds of

symmetry,

_l_ _l_

-------- = ---------

φ(_v_) φ(-_v_)

∴ φ(_v_) = φ(-_v_), ∴ φ(_v_) = 1.

§ 4. The physical significance of the equations obtained concerning

moving rigid bodies and moving clocks.

Let us consider a rigid sphere (_i.e._, one having a spherical figure

when tested in the stationary system) of radius R which is at rest

relative to the system (K), and whose centre coincides with the origin

of K then the equation of the surface of this sphere, which is moving

with a velocity _v_ relative to K, is

ξ² + η² + ζ² = R².

At time _t_ = 0, the equation is expressed by means of (_x_, _y_, _z_,

_t_,) as

$$ \frac {x^2}{(\sqrt {1 - \frac {v_2}{c_2}})^2} + y^2 + z^2 = R^2. $$

A rigid body which has the figure of a sphere when measured in the

moving system, has therefore in the moving condition—when considered

from the stationary system, the figure of a rotational ellipsoid with

semi-axes

$$ R \sqrt {1 - \frac {v^2}{c^2}}, R, R. $$

Therefore the _y_ and _z_ dimensions of the sphere (therefore of any

figure also) do not appear to be modified by the motion, but the _x_

dimension is shortened in the ratio

$$ 1 : \sqrt {1 - \frac {v^2}{c^2}}; $$

the shortening is the larger, the larger is _v_. For _v_ = _c_, all

moving bodies, when considered from a stationary system shrink into

planes. For a velocity larger than the velocity of light, our

propositions become meaningless; in our theory _c_ plays the part of

infinite velocity.

It is clear that similar results hold about stationary bodies in a

stationary system when considered from a uniformly moving system.

Let us now consider that a clock which is lying at rest in the

stationary system gives the time _t_, and lying at rest relative to the

moving system is capable of giving the time τ; suppose it to be placed

at the origin of the moving system _k_, and to be so arranged that it

gives the time τ. How much does the clock gain, when viewed from the

stationary system K? We have,

$$ \tau = \frac {1}{\sqrt {1-\frac {v^2}{c^2}}} (t - \frac {v}{c^2}x),

$$

and _x_ = _vt_,

$$ \therefore \tau - t = (1 - \sqrt {1 - \frac {v^2}{c^2}}) t. $$

Therefore the clock loses by an amount ½(_v²_/_c²_) per second of

motion, to the second order of approximation.

From this, the following peculiar consequence follows. Suppose at two

points A and B of the stationary system two clocks are given which are

synchronous in the sense explained in § 3 when viewed from the

stationary system. Suppose the clock at A to be set in motion in the

line joining it with B, then after the arrival of the clock at B, they

will no longer be found synchronous, but the clock which was set in

motion from A will lag behind the clock which had been all along at B by

an amount ½_t_(_v²_/_c²_), where _t_ is the time required for the

journey.

We see forthwith that the result holds also when the clock moves from A

to B by a polygonal line, and also when A and B coincide.

If we assume that the result obtained for a polygonal line holds also

for a curved line, we obtain the following law. If at A, there be two

synchronous clocks, and if we set in motion one of them with a constant

velocity along a closed curve till it comes back to A, the journey being

completed in _t_-seconds, then after arrival, the last mentioned clock

will be behind the stationary one by ½_t_(_v²_/_c²_) seconds. From this,

we conclude that a clock placed at the equator must be slower by a very

small amount than a similarly constructed clock which is placed at the

pole, all other conditions being identical.

§ 5. Addition-Theorem of Velocities.

Let a point move in the system _k_ (which moves with velocity _v_ along

the _x_-axis of the system K) according to the equation

$$ \xi = w_{\xi} \tau, \eta = w_{\eta} \tau, \zeta = 0, $$

where _w__{ξ} and _w__{η} are constants.

It is required to find out the motion of the point relative to the

system K. If we now introduce the system of equations in § 3 in the

equation of motion of the point, we obtain

$$ x = (\frac {w_{\xi} + v}{1+\frac {vw_{\xi}}{c^2}}) t $$,

$$ y = \frac {(1-\frac {v^2}{c^2})^{\frac {1}{2}} w_{\eta}t} {1+\frac

{vw_{\xi}}{c^2}} $$ ,

z = 0 .

The law of parallelogram of velocities hold up to the first order of

approximation. We can put

$$ U^2 = (\frac {\partial x}{\partial t})^2 + (\frac {\partial

y}{\partial t})^2 $$ ,

$$ w^2 = w_{\xi}^2 + w_{\eta}^2 $$ ,

and

$$ \alpha = tan^{-1} \frac {w}{w_{\xi}} $$

_i.e._, α is put equal to the angle between the velocities _v_, and _w_.

Then we have—

$$ U = \frac {[(v^2 + w^2 + 2 vw \cos \alpha) - (\frac {vw \sin

\alpha}{c})^2]^{\frac {1}{2}}} {1 + \frac {vw \cos \alpha}{c^2}} $$

It should be noticed that _v_ and _w_ enter into the expression for

velocity symmetrically. If _w_ has the direction of the ξ-axis of the

moving system,

$$ U = \frac {v + w}{1 + \frac {vw}{c^2}} $$

From this equation, we see that by combining two velocities, each of

which is smaller than _c_, we obtain a velocity which is always smaller

than _c_. If we put _v_ = _c_ - χ, and _w_ = _c_ - λ, where χ and λ are

each smaller than _c_,[8]

$$ U = c \frac {2c - \chi - \lambda}{2c - \chi - \lambda + \frac {\chi

\lambda}{c^2}} < c $$

It is also clear that the velocity of light _c_ cannot be altered by

adding to it a velocity smaller than _c_. For this case,

$$ U = \frac {c + v}{1 + \frac {cv}{c^2}} = c $$

We have obtained the formula for U for the case when _v_ and _w_ have

the same direction; it can also be obtained by combining two

transformations according to section § 3. If in addition to the systems

K, and k, we introduce the system k´, of which the initial point moves

parallel to the ξ-axis with velocity _w_, then between the magnitudes,

_x_, _y_, _z_, _t_ and the corresponding magnitudes of k´, we obtain a

system of equations, which differ from the equations in § 3, only in the

respect that in place of _v_, we shall have to write,

$$ \frac {v + w}{1 + \frac {vw}{c^2}} $$

We see that such a parallel transformation forms a group.

We have deduced the kinematics corresponding to our two fundamental

principles for the laws necessary for us, and we shall now pass over to

their application in electrodynamics.

The Principle of Relativity · 第 26 / 203 题