CHAPTER XX

COMMUTATION AND THE COMMUTATOR

The act of commutation needs special study. If it be incorrectly

performed, the imperfection at once manifests itself by sparks which

appear at the brushes. In the study of this chapter on commutation it

would be advisable for the student to first review the basic principles

of commutation as given in chapter XIV, which contains a brief and

simple explanation of how the alternating current in the armature is

converted into direct current by the action of the commutator.

=Ques. What is the period of commutation?=

Ans. The time required for commutation, or the angle through which the

armature must turn to commute the current in one coil.

=Ques. Upon what does the period of commutation depend?=

Ans. Upon the width of the brushes as shown in fig. 300.

This fixes the angle through which the armature must revolve

to commute the current in one coil. This angle is formed, as

shown in the figure, by two intersecting planes, M and S, which

pass through the axis of the armature and the two edges of the

brush. Commutation then, begins at M and ends at S.

=Ques. What is the position of the commutating plane with respect to

M and S, in fig. 300?=

Ans. It bisects the angle formed by the planes M and S.

[Illustration: FIG. 300.--Armature with one brush in position

to illustrate the _period of commutation_ and _commutating plane_. The

latter is called "commutating line" by some writers. The period of

commutation depends on the thickness of the brush end in contact with

the commutator. Careful distinction should be made between _commutating

plane_, _neutral plane_, and _normal neutral plane_ as defined

elsewhere.]

=Ques. What is the the commutating plane?=

Ans. An imaginary plane passing through the axis of the armature and

the center of contact of the brush.

=Ques. What two planes are referred to in stating the position of the

brushes?=

Ans. The normal neutral plane and the commutating plane.

The angle intercepted by these two planes represents the

_lead_, thus in stating that the brushes have a lead of 6°,

means that the angle intercepted by the normal neutral plane

and the commutating plane is 6°.

[Illustration: FIG. 301.--The proper position of the brushes,

if there were no field distortion and self-induction in the armature

coils, would be in the normal neutral plane. In the actual dynamo

these two disturbing effects are present which makes it necessary to

advance the brushes as shown in figs. 302 and 303 to secure sparkless

commutation.]

=Ques. What is the difference between the normal neutral plane and

the neutral plane?=

Ans. This is illustrated in figs. 301 and 302. _The normal neutral

plane is the position of zero induction assuming no distortion of

the field_ as in fig. 301. _The neutral plane is the position of zero

induction with distorted field_ as in fig. 302 and as is found in

the actual machine; the distortion is exaggerated in the figure for

clearness.

[Illustration: FIG. 302.--Brush adjustment for field

distortion. The effect of the latter is to twist the lines of force

around in the direction of rotation, thus maximum induction takes place

in an inclined plane. The brushes then must be advanced to the _neutral

plane_ which is at right angles to the plane of maximum induction. This

gives the proper position of the brushes _neglecting self-induction_.]

=Ques. What is the normal plane of maximum induction?=

Ans. _A plane, 90° in advance of the normal neutral plane_, being the

position of maximum induction with no distortion of field, as in fig.

301.

=Ques. What is the plane of maximum induction?=

Ans. _A plane 90° in advance of the neutral plane_, being the position

of maximum induction in a distorted field as in fig. 302.

[Illustration: FIG. 303.--Brush adjustment for self-induction.

For convenience an electric current is regarded as having weight and

hence possessing the property of inertia. The current then during

commutation cannot be instantly brought to rest and started in the

reverse direction but these changes must be brought about gradually

by an opposing force. Hence by advancing the brushes beyond the

neutral plane as illustrated, commutation takes place with the short

circuited coil cutting the lines of force so as to induce a current in

the opposite direction; this opposes the motion of the current in the

short circuited coil, brings it to rest and starts it in the opposite

direction, thus preventing sparks. Figs. 301 to 303 should be carefully

compared and thoroughly understood.]

=Ques. What should be noted with respect to the different planes?=

Ans. The commutating plane should be carefully distinguished from the

normal neutral plane and from the neutral plane, as shown in fig. 303.

=Commutation.=--In order to understand just what happens during

commutation, a section of a ring armature may be used for illustration,

such as shown in fig. 304. Here the coils A, B, C, D, E, are connected

to commutator segments 1, 2, 3, 4, and the positive brush is shown

in contact with two segments 2 and 3, the brush being in the neutral

position. Currents in the coils on each side of the neutral line flow

to the brush through segments 2 and 3; the brush then is positive.

[Illustration: FIG. 304.--Commutation. This takes place during

the brief interval in which any two segments of the commutator are

bridged by the brush. The coil connecting with the two segments under

the brush is thus short circuited. During commutation the current in

the short circuited coil is brought to rest and started again in the

reverse direction against the opposition offered by its so called

inertia, or effect produced by self-induction.]

Now, as the armature turns, the commutator segments come successively

into contact with the brush. In the figure, segment 3 is just leaving

the brush and 2 is beginning to pass under it, hence, for an instant

the coil C is short circuited.

=Ques. In fig. 304, what are the current conditions?=

Ans. Previous to contact with segment 2, current flowed in coil C in

the same direction as in coil B.

=Ques. What occurs while the brush is in contact with segments 2 and

3?=

Ans. During this brief interval, the current in C is stopped and

started again in the opposite direction.

Similarly each coil of the armature as it passes the brush will

be short circuited and have its current reversed. This is known

as _commutation_.

=Ques. What is the effect of field distortion with respect to

commutation?=

Ans. The neutral plane no longer coincides with the normal neutral

plane but is advanced in the direction of rotation of the armature as

shown in fig. 302.

The reaction of the poles N' and S' of the armature field on

the poles S and N of the main magnetic field tends to crowd

the lines of force into the upper pole face of the south pole

of the magnet, and into the lower pole face of the north pole.

This effect is due to the strong magnetic attraction between

the opposite poles S and N' and N and S', and the equally

strong repulsion between like poles N and N' and S and S'.

Hence, the plane of maximum induction no longer coincides

with the normal plane of maximum induction, but is advanced

in the direction of rotation, depending upon the strength of

the armature current, being shifted forward for an increase

of current, and backward for a decrease of current. This

distortion of the field and the consequent shifting of the

plane of maximum induction naturally results in the shifting of

the neutral plane from the vertical position to the inclined

position as shown.

=Position of the Brushes; Sparking.=--In accordance with the

laws of electromagnetic induction, if the bipolar ring armature shown

in fig. 301 be rotated in the direction indicated by the arrow the

armature current entering at the brush E will divide, one part passing

through the coils on the right half of the ring, and the other part

through the coils on the left half of the ring, to the brush F, from

which the total current will pass out, urged by the full value of the

electromotive force induced in all the coils on both halves of the ring.

[Illustration: FIGS. 305 to 308--Improper brush adjustment

resulting in excessive sparking. When the brushes are not advanced far

enough, commutation takes place before the short circuited coil reaches

the neutral plane, hence, its motion is not changed with respect

to the magnetic field so as to induce a reverse current till after

commutation. There is then no opposing force, during commutation, to

stop and reverse the current in the short circuited coil, and when the

brush breaks contact with segment 1, as in fig. 308, the "_momentum_"

of the current in coil F causes it to jump the air gap from segment 1

to segment 2 and the brush, against the enormous resistance of the air,

thus producing a spark whose intensity depends on the momentum of the

current in coil F. Sparking, if allowed to continue, will injure the

brushes and commutator segments.]

Again, if the brushes be placed at the points G and H, each half of a

current entering at G, will pass through one-half of the coils on the

left side and one-half of the coils on the right side of the ring, so

that each half of the current will be urged forward by an electromotive

force equal to the electromotive force tending to force it back, and

therefore, no current will pass in or out through the brushes. From

these considerations it is obvious that the proper position for the

brushes would be in the normal neutral plane, _were it not for the

disturbing effects of armature reaction and self induction of the

current_.

=Ques. Should the brushes of a dynamo be placed in the neutral

plane?=

Ans. No.

=Ques. Why not?=

Ans. The brushes must be advanced beyond the neutral plane to prevent

sparking.

=Ques. What is the cause of sparking at the brushes?=

Ans. It is due to _self-induction_ in the coil undergoing commutation.

=Ques. Explain the effect of self-induction in detail.=

Ans. When commutation takes place with the brushes in the neutral

plane as in fig. 304, there will be no voltage induced in the short

circuited coil C. The current, therefore, which flowed in coil C before

it was short circuited will cease, and as segment 3 breaks contact with

the brush, it will be thrown as a perfectly idle coil upon the right

hand half of the ring in which a current is flowing toward the brush.

Moreover, the current which was flowing through D and 3 directly to the

brush, must suddenly traverse the longer path through the idle coil C.

Now, on account of self-induction, _the current acts in precisely the

same manner as though it had weight_; that is:

_It cannot be instantly stopped or started._

[Illustration: FIGS. 309 to 313.--How sparkless commutation is

obtained by advancing the brushes beyond the neutral plane; commutation

progressively shown.]

[Illustration: FIG. 309.--Commutation begins; current flows

up both sides of the armature, uniting at S and flowing to the brush

through commutator segment 1 as indicated by the arrow.]

[Illustration: FIG. 310.--Segment 2 has come into contact

with the brush and coil F, in which commutation is taking place, is

now short circuited. The current now divides at M, part passing to

the brush through segment 2, and part through coil F and segment 1.

Although coil F is short circuited and having passed the neutral plane,

is cutting the lines of force so as to induce a current in the opposite

direction, it still continues to flow with unchanged direction against

these opposing conditions. This is due to _self-induction_ in the coil

which resists any change just as the momentum of a heavy moving body,

such as a train of cars, offers resistance to the action of the brakes

in retarding and stopping its motion.]

Therefore, when segment 3 leaves the brush, the current will not

instantly change its path and flow through C, but will be urged by its

"_momentum_," and jump the air gap between the brush and segment 3,

thus producing a spark.

[Illustration: FIG. 311.--Segment 2 has moved further under

the brush, and the opposition offered to the forward flow of the

current in the short circuited coil F by the reverse induction in the

magnetic field to the right of the neutral plane has finally brought

the current in F to rest. The currents from each side of the armature

now flow direct to the brush through their respective end segments 1

and 2.]

[Illustration: FIG. 312.--Segment 1 is now almost out of

contact with the brush. A current has now been started in the coil F

in the reverse direction due to induction in the magnetic field to the

right of the neutral plane; it flows to the brush through segment 2.

The current has not yet reached its full strength in F, accordingly,

part of the current coming up from the right divides at S and flows to

the brush through segment 1.]

[Illustration: FIG. 313.--Completion of commutation in

segments 1 and 2; the brush is now in full contact with segment 2, the

current in coil F has now reached its full value, hence the current

flowing up from the right no longer divides at S but flows through F

and segment 2 to the brush. If the current in F had not reached its

full value, at the instant segment 1 left contact with the brush, it

could not immediately be made to flow at full speed any more than could

a locomotive have its speed instantly changed. This, as previously

explained, is due to self-induction in the coil or the so called

"inertia" of the current which opposes any sudden change in its rate of

flow or direction. Accordingly that portion of the current which was

flowing up from the right and passing off at S to the brush through

segment 1 as in fig. 312, would, when this path is suddenly cut off as

in fig. 313, encounter enormous opposition in coil F. Hence, it would

momentarily continue to flow through segment 1 and jump the air gap

between this segment and the brush, resulting in a more or less intense

spark depending on the current conditions in coil F.]

=Ques. How may this sparking be prevented?=

Ans. If the brushes be given additional lead, that is shifted further

to the right to some position as N N, fig. 304, coil C will not

remain idle during the interval it is short circuited, _but will

cut the magnetic lines in such a way as to induce a current in the

reverse direction through it_. Under these conditions, when segment 3

breaks contact with the brush, the current flowing through D does not

encounter an idle coil, but one in which a current is flowing in the

same direction, hence, the tendency to jump the air gap and produce a

spark is reduced; with proper adjustment of the brushes, there will be

no sparking.

=Ques. What is the objection to very thin brushes?=

Ans. Time must be allowed for reversal of the current, hence the

brushes must not be so thin as merely to bridge the insulation between

segments.

=Ques. What is the effect of lead?=

Ans. There is usually much sparking when the lead is too small; a

little sparking when too great, and no sparking when just right. If the

lead be excessive, there is a waste of energy due to the generation of

a larger reverse current in the short circuited coil than is necessary.

=Fixed Position of Brushes.=--The condition for sparkless

commutation is that the current in the short circuited coil be reduced

to zero, and increased in the opposite direction up to the same value

as that in the next coil leading. If the brushes are to remain in a

fixed position, this condition will only be realized at the particular

load for which the brushes are set. Thus, if the brushes be set for

the average load, the reversing field will not be correct for either

a weaker or stronger load. Hence, sparkless commutation with fixed

brushes must be due to some other factor.

=Ques. What may be said with respect to carbon brushes?=

Ans. Since carbon possesses a high resistance, the drop will vary

greatly with the contact area, thus affecting a difference of potential

in the two segments passing under the brush and it is largely to this

that sparkless commutation is due.

=Ques. What is the effect of resistance on commutation?=

Ans. In fig. 304 during commutation, that is, while the brush contacts

with any two segments, as 2 and 3, the currents coming up through the

winding on either side of the neutral plane are offered two paths to

the brush: 1, direct to brush through the connecting segment, or 2,

across the short circuited coil and adjacent segment. Thus, on the

right side: to brush through segment 3, or across coil C and adjacent

segment 2.

_The current will take the path of least resistance._

At the beginning of commutation, almost the entire brush area being in

contact with segment 3, the contact resistance of this segment will

be much less than for segment 2; hence, not only will the current

at the right flow through 3, but also the current at the left after

first traversing the short circuited coil. As commutation progresses,

the area of contact of 3 decreases while that of 2 increases, and

the respective resistances vary in inverse proportion. Likewise the

tendency of the current in the left half of the winding to take the

longer path through coil C and segment 3 to the brush gradually

decreases, becoming zero when the two contact areas become equal.

During the second half of the period of commutation, the contact area

of segment 2 becomes greater and of 3, less; thus the resistance of 2

is lowered, and that of 3 increased. Accordingly, all of the current

at the left will flow through segment 2, and the current at the right

will flow through C and 2 rather than through 3. In this way the

current is reversed in C, and, if the brush be broad enough to allow

a sufficient time interval, the current in C is built up to its full

value before segment 3 leaves the brush, thus securing sparkless

commutation.

This contact resistance factor in sparkless commutation

is illustrated in figs. 314 to 318, it being assumed that

during commutation, the brush contact resistance is inversely

proportional to the area of contact, and that the winding is

free of resistance and inductance. The current is taken as 40

amperes, in which case 20 amperes will flow from each side of

the winding to the brush.

In fig. 314 the instant before commutation begins all the

current will flow through segment A. At the end of the first

quarter of the period of commutation, fig. 315, 30 amperes will

flow from the right to brush through A, and from the left, 10

amperes through the short circuited coil via A and 10 amperes

through B.

At the end of the second quarter or half period, fig, 316, the

current through each half of the winding will flow to the brush

through these respective segments.

At the end of the third quarter, fig. 317, the current from the

right will divide, 10 amperes going through A, and 30 amperes

traversing the short circuited coil and out through B. The

entire current from the left will flow through segment B.

At the end of the fourth quarter, fig. 318, or completion of

the period the current from each half of the winding will flow

to the brush through B.

[Illustration: FIGS. 314 to 318.--Brush contact resistance

theory of commutation, neglecting self-induction and resistance in the

coils. The total current is assumed to be 40 amperes made up of 20

amperes flowing toward the brush from the coils on the right and 20

amperes from the coils on the left. During commutation, that is, the

interval during which the brush contacts with any two adjacent segments

of the commutator, the current is assumed to vary directly as the

contact area.]

[Illustration: FIG. 314.--Beginning of commutation; segment A

is entirely under the brush, and B is at the initial point of contact.

For this position the currents from both sides flow to the brush

through segment A.]

[Illustration: FIG. 315.--One-quarter period of commutation.

One quarter of the brush area is in contact with B and three quarters

in contact with A; hence, 10 amperes will flow through B and 30 amperes

through A.]

[Illustration: FIG. 316.--Second quarter of commutation

period. The brush now contacts equally with both segments, hence 20

amperes will flow through each segment.]

[Illustration: FIG. 317.--Third quarter of commutation period.

Three quarters of the brush area is in contact with segment B and one

quarter with segment A; accordingly, 30 amperes will flow through B and

10 amperes through A.]

[Illustration: FIG. 318.--Completion of commutation. The brush

is in full contact with segment B and at the point of breaking contact

with A, hence the entire current from both sides or 40 amperes will

flow through B.]

[Illustration: FIGS. 319 to 323.--Brush contact theory of

commutation for case in which the brush covers two segments of the

commutator. Fig. 319 beginning of commutation; fig. 320 one-quarter

period; fig. 321, one-half period; fig. 322, three-quarter period; fig.

323 completion of commutation.]

=Ques. What is the effect of increasing the degree of contact of the

brushes?=

Ans. It lengthens the period of commutation, and permits it to start

in one coil before the preceding coil has entirely passed through this

stage.

The effect of changing the degree of contact is shown in figs.

319 to 323, in which the width of the brush is made equal to

that of two segments.

=Construction of Commutators.=--The commutator for a closed coil

armature consists of a number of segments or L-shaped bars C of drop

forged hard drawn copper assembled around a tubular iron hub as shown

in figs. 324 and 325. The bars are held in position by the nuts E, and

washers F, screwed on the ends of the tube D. The bars are insulated

from each other and from the washers by mica as shown by the heavy

lines G, and they are also insulated from the tube either by a tube

of mica H, or by a sufficient air space. The ends of the sections

of winding are connected to the vertical portions of the bars K, by

insertion in the slots L, where they are securely held in place by

means of the binding screws, which for greater security are soldered

together, and may be released from the slots, whenever necessary, by

the application of a hot soldering iron.

[Illustration: FIGS. 324 and 325.--Side and end sectional

views of commutator showing construction. The parts are: C, segments;

D, tubular iron hub; E, end nuts; F, clamps; G, insulation; L, riser

connection.]

It is very important that all the parts of the commutator should be

fitted together perfectly and screwed up tightly, in order to prevent

looseness. Commutator segments are often made with the washers E,

projecting beyond the ends, but such construction reduces the effective

length of the commutator, therefore the under cut form of bar is

preferable.

In the construction of commutators, the conditions of operation require

that there be:

1. Adequate insulation;

It is necessary to have good insulation between each segment,

and a specially good insulation between the segments and the

hub or sleeve on which they are mounted; also between the

segments and end clamps. The insulating material must not

absorb moisture, hence asbestos, plaster, or vulcanized fibre

are not used. The end insulating rings are usually built up

of mica and shellac, moulded while hot under pressure to the

correct shape.

[Illustration: FIG. 326.--Front view of Western Electric

Commutator for bar wound armature. This commutator is made of hard

drawn copper and insulated throughout, ventilating spaces being

provided near the shaft.]

2. Rigidity against centrifugal force;

Since the segments are subject to centrifugal force, they

must be securely clamped in place. Screws cannot be used, for

that would destroy the insulation. They are therefore held in

place by insulated clamps as shown in fig. 324. These clamps

should be strong and capable of holding the segments firmly in

position, for if a segment should rise out of its place through

centrifugal force, it would disturb the action of the brush and

cause sparking.

3. Provision for wear.

The segments should be of considerable radial depth, so that

the commutator may be turned down from time to time to preserve

its circular form.

[Illustration: FIG. 327.--Sectional view of a General

Electric commutator. The segments are of rolled or forged copper and

are separated by soft mica insulating sheets. This mica must wear

down evenly with the copper, hence its consistency is important. The

segments are wedge shaped so that when drawn radially inward they

support each other like the stones of an arch. They are drawn together

by hollow cone collars which bear upon lugs projecting from the ends

of the segments. These lugs are turned to form a smooth cone after the

segments are assembled. The collars are insulated with mica from the

segments and they are held in place by nuts upon the commutator shell

or by bolts passing from end to end under the segments. The segments

are also provided with lugs for connection to the windings.]

=Points Relating to Commutators.=--1. The number of commutator

segments depends on the scheme of winding and on the number of sections

in the armature winding.

2. Increasing the number of bars diminishes the tendency to spark, and

lessens the fluctuations of the current.

There are two practical reasons for not using a very great

number of segments: it increases the cost, and in small

machines the segments would be so thin that a brush of the

proper thickness to collect the current would lap over, or

bridge several segments.

=Types of Commutator.=--Commutators are made in various forms, but

they may be grouped into two general types:

1. Commutators for closed coil armatures;

These consist of a large number of segments or bars, insulated

from each other and varying in number according to the scheme

of armature winding, and on the number of sections into which

that winding is grouped.

[Illustration: FIG. 328.--A large current low voltage bipolar

dynamo built for electrolytic work and here shown to illustrate the

large size commutator and brushes necessary to collect the large

current. Carbon brushes would not be suitable for this class of machine

because even with copper brushes, whose conductivity is much higher

than carbon, the commutator must be of considerable size to give the

required brush contact area. The contrast between the axial lengths of

the armature and the commutator is very marked. The rocker construction

is of the ordinary type, and heavy flexible cables conduct the current

from the brush holders to the fixed terminals. The machine here

illustrated gives 310 amperes at 7 volts when running at a speed of

1400 R. P. M., corresponding to an output of 2.17 kilowatts.]

2. Commutators for open coil armatures;

This form of commutator is used on some machines designed

especially for arc lighting, such as the Brush and

Thompson-Houston machines. They consist of a comparatively

small number of segments each of which covers a wide angle, and

are separated from each other by air gaps.

3. The segments should be of considerable depth to permit returning

occasionally so that their circular form may be preserved;

4. The insulating material must be such that it will not absorb oil or

moisture;

Mica is best adapted for insulation, but as there are a great

many varieties, differing greatly in hardness and other

equalities, it is important to select the kind that wears at

the same rate as the segments. If the mica be too hard, the

wearing of the segments will leave it projecting and prevent

proper contact with the brushes; again, if the mica be too

soft, it will result in furrows or depressions between the

segments into which copper dust will collect, causing short

circuits.

Hawkins Electrical Guide v. 02 (of 10) Questions, Answers, & Illustrations, A progressive course of study for engineers, electricians, students and those desiring to acquire a working knowledge of electricity and its applications · 第 4 / 9 章