In the general case--

if z1 is the co-latitude of the centre of the map, z the co-latitude

of any other point, [alpha] the difference of longitude of the two

points, A the azimuth of the line joining them, and c the spherical

length of the line joining them, then the position of the intersection

of any meridian with any parallel is given (on the spherical

assumption) by the solution of a simple spherical triangle.

Encyclopaedia Britannica, 11th Edition, "Map" to "Mars" Volume 17, Slice 6 · 第 14 / 41 题