The solution of this amusing problem is as follows: The fugitive started
from station No. 1 on foot, carrying the child; at station No. 2 he
mounted a bicycle and, still carrying the child, rode to No. 3; there he
placed the child in a wheelbarrow; as indicated by the marks of the legs
of the wheelbarrow, he stopped before reaching No. 4 and put down the
child, who walked by his side to the station; thence he continued his
journey on a tricycle, which also carried the child; at No. 5 he changed
his tricycle for a monocycle (that is, a single-wheeled cycle, such as
is used by trick-riders), but the child which he was carrying caused him
to lose his balance and he fell; he then took the child in his arms and
carried it to No. 6; thence he started holding the child by the hand,
but farther on he again took it in his arms and so completed the journey
at No. 7.