66.4: 52.5 = _x_: 26.048

Whence _x_ = 32.74.

In the one case three times the normal weight of milk is 61.53 and in

the other twice the normal weight, 65.48 grams.

=244. Error due to Volume of Precipitate.=—Vieth states that the

volume allowed for the precipitated solids in the original process,

_viz._, two and four-tenths cubic centimeters, is not sufficiently

large.[202] In such cases it is quite difficult to decide on any

arbitrary correction based on the supposed quantities of fat and

albuminoids present. A better method than to try to compensate for

any arbitrary volume is to remove entirely the disturbing cause or

eliminate it by indirect means. To wash the precipitate free of sugar

without increasing the bulk of the filtrate unduly would be extremely

difficult and tend, moreover, to bring some of the precipitated matters

again into solution. It is better, therefore, to eliminate the error by

double dilution and polarization (=86=). The principle of this method

is based on the fact, that, within limits not sensibly affecting the

gyrodynat by reason of different densities, the polarizations of two

solutions of the same substance are inversely proportional to their

volumes.

For convenience, it is recommended that the volumes of the samples in

each instance be 100 and 200 cubic centimeters, respectively, in which

case the true reading is obtained by the simple formula given in the

latter part of =86=.

In this laboratory the double dilution method of determining the volume

of the precipitate is conducted as follows:[203]

In each of two flasks marked at 100 and 200 cubic centimeters,

respectively, are placed 65.52 grams of milk, four cubic centimeters

of mercuric nitrate added, the volume completed to the mark and the

contents of the flask well shaken.

After filtering, the polarization is made in a 400 millimeter tube

by means of the triple shadow polariscope described in =75=. From

the reading thus obtained the volume of the precipitate and the

degree of correction to be applied are calculated as in the subjoined

example. The flasks should be filled at near the temperature at which

the polarizations are made and the observation room must be kept at

practically a constant temperature of 20° to avoid the complications

which would be produced by changes in the gyrodynat of lactose and

the value of the quartz plates and wedges of the apparatus by marked

variations in temperature.

_Example._—Weight of milk used in each case 65.52 grams.

Polarimetric reading from the 100 cubic centimeter flask, 20°.84

” ” ” ” 200 ” ” ” 10°.15

Then 10.15 × 2 = 20.30

20.84 - 20.30 = 0.54

0.54 × 2 = 1.08

20.84 - 1.08 = 19.76

19.76 ÷ 4 = 4.94,

which is the corrected reading showing the percentage of lactose in the

sample used.

The volume of the precipitate is calculated as follows:

20.84 ÷ 4 = 5.21, the apparent percentage of lactose present.

Then 5.21: 4.94 = 100: _x_.

Whence _x_ = 94.82. From this number it is seen that the true volume of

the milk solution polarized is 94.82 instead of 100 cubic centimeters,

whence the volume occupied by the precipitate is 100 - 94.82 = 5.18

cubic centimeters. So little time is required to conduct the analysis

by the double dilution method as to render it preferable in all cases

where incontestable data are desired. Where arbitrary corrections are

made the volume allowed for the precipitate may vary from two and a

half cubic centimeters in milks poor in fat, to six for those with a

high cream content.

For milks of average composition sufficient accuracy is secured by

making an arbitrary correction of five cubic centimeters for the volume

of the precipitate.

Principles and practice of agricultural analysis. Volume 3 (of 3), Agricultural products · 第 97 / 164 题