DETECTION AND ESTIMATION OF FUSEL OIL.

Until quite recently we have had no accurate method for the

determination of fusel oil in alcohol or brandy. In 1837 Meurer

suggested a solution of one part of silver nitrate in nine parts of

water as a reagent for its detection, stating that when added to alcohol

containing fusel oil, a reddish brown color is produced, and in case

large quantities are present, a dark brown precipitate is formed. It was

soon found, however, that other substances than amyl alcohol produce

brown colored solutions with silver nitrate; and Bouvier[1] observed

that on adding potassium iodide to alcohol containing fusel oil, the

solution is colored yellow, from the decomposition of the iodide.

Subsequently Boettger[2] proved that potassium iodide is not decomposed

by pure amyl alcohol, and that the decomposition is due to the presence

of acids contained in fusel oil. More accurate results are obtained by

using a very dilute solution of potassium permanganate, which is

decomposed by amyl alcohol much more rapidly than by ethyl alcohol.

[Footnote 1: Zeitschrift f. Anal. Chem. xi., 343.]

[Footnote 2: Dingler's Polytech. Jour., ccxii., 516.]

Depre[3] determines fusel oil by oxidizing a definite quantity of the

alcohol in a closed vessel with potassium bichromate and sulphuric acid.

after removal of excess of the oxidizing reagents, the organic acids are

distilled, and, by repeated fractional distillation, the acetic acid is

separated as completely as possible. The remaining acids are saturated

with barium hydroxide, and the salts analyzed; a difference between the

percentage of barium found and that of barium in barium acetate proves

the presence of fusel oil, and the amount of difference gives some idea

of its quantity. Betelli[4] dilutes 5 c.c. of the alcohol to be tested

with 6 to 7 volumes of water, and adds 15 to 20 drops of chloroform and

shakes thoroughly. If fusel oil is present, its odor may be detected by

evaporating the chloroform; or, by treatment with sulphuric acid and

sodium acetate, the ether is obtained, which can be readily recognized.

Jorissen[5] tests for fusel oil by adding 10 drops of colorless aniline

and 2 to 3 drops of hydrochloric acid to 10 c.c. of the alcohol. In the

presence of fusel oil a red color is produced within a short time, which

can be detected when not more than 0.1 per cent. is present. But

Foerster[6] objects to this method because he finds the color to be due

to the presence of furfurol, and that pure amyl alcohol gives no color

with aniline and hydrochloric acid.

[Footnote 3: Pharm. J. Trans. [3] vi., 867.]

[Footnote 4: Berichte d. Deutschen Chem. Gesellsch., viii., 72.]

[Footnote 5: Pharm. Centralhalle, xxii., 3.]

[Footnote 6: Berichte d. Deutsch. Chem. Gesellsch., xv., 230.]

Hager[7] detects fusel oil as follows: If the spirit contains more than

60 per cent. of alcohol, it is diluted with an equal volume of water and

some glycerine added, pieces of filter paper are then saturated with the

liquid and exposed to the After the evaporation of the alcohol, the odor

of the fusel oil can be readily detected. For the quantitative

determination he distills 100 c.c. of the alcohol in a flask of 150 to

200 c.c. capacity connected with a condenser, and so arranged that the

apparatus does not extend more than 20 cm. above the water bath. This

arrangement prevents the fusel oil from passing over. If the alcohol is

stronger than 70 per cent., and the height of the distillation apparatus

is not more than 17 cm., the residue in the flask may be weighed as

fusel oil. With a weaker alcohol, or an apparatus which projects further

out of the water bath, the residual fusel oil is mixed with water. It

can, however, be separated by adding strong alcohol and redistilling, or

by treating with ether, which dissolves the amyl alcohol, and

distilling, the temperature being raised finally to 60 deg..

[Footnote 7: Pharm. Centralhalle, xxii., 236.]

Marquardt,[8] like Betelli, extracts the fusel oil from alcohol by means

of chloroform, and by oxidation converts it into valeric acid. From the

quantity of barium valerate found he calculates the amount of amyl

alcohol present in the original solution; 150 c.c. of the spirit, which

has been diluted so as to contain 12 to 15 per cent. of alcohol, are

shaken up thoroughly with 50 c.c. of chloroform, the aqueous layer drawn

off, and shaken with a fresh portion of chloroform. This treatment is

repeated several times. The extracts are then united, and washed

repeatedly with water. The chloroform, which is now free from alcohol

and contains all the fusel oil, is treated with a solution of 5 grammes

of potassium bichromate in 30 grammes of water and 2 grammes of

sulphuric acid, and then heated in a closed flask for six hours on a

water bath at 85 deg.. The contents of the flask are then distilled, the

distillate saturated with barium carbonate, and the chloroform

distilled; the residue is evaporated to a small volume, the excess of

barium carbonate filtered off, and the filtrate evaporated to dryness

and weighed. The residue is dissolved in water, a few drops of nitric

acid added, and the solution divided into two portions. In the first

portion the barium is determined; in the second the barium chloride. The

total per cent. of barium minus that of barium chloride gives the amount

present as barium valerate, from which is calculated the per cent. of

amyl alcohol. By this process the author has determined one part of

fusel oil in ten thousand of alcohol. To detect very minute quantities

of fusel oil, the chloroform extracts are treated with several drops of

sulphuric acid and enough potassium permanganate to keep the solution

red for twenty-four hours. If allowed to stand in a test tube, the odor

of valeric aldehyde will first be noticed, then that of amyl valerate,

and lastly that of valeric acid.--_Amer. Chem. Journal._

[Footnote 8: Berichte d. Deutsch. Chem. Gesellsch., xv., 1,370

and 1,663.]

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Scientific American Supplement, No. 365, December 30, 1882 · 第 15 / 48 题