NO. I.

_Determination of the Influence of Internal Stresses on the Strength of

Materials._--We call internal stresses those which exist within the mass

of any hollow cylinder or other body, when it appears to be in a state

of repose, or not under the influence of external forces. When pressure

is applied to a hollow cylinder, either externally or internally, the

interior layers into which its walls may be conceived to be divided are

subjected to a new series of stresses, the magnitude of which is

independent of those already existing. These additional stresses combine

with the former in such a manner that at every point of the thickness of

the cylinder they have common resultants acting in various directions.

Thus, if we call t the internal stress existing at a distance r_x

from the axis of the cylinder, and in a direction tangential to its

cross section, and T the additional stress due to pressure inside the

cylinder acting at the same point and in the same direction, then the

newly developed stress will be t + T.

If R and r0 be the external and internal radii of the cylinder, and

if we suppose the external pressure _nil_, then, if the pressure inside

the bore be P0, the stress on the radius r_x is determined by the

following expression deduced from the well-known fundamental formulæ of

Lame:[1]

r0² R² + (r_x)²

T = P0 ------- · -------------

R²-r0² (r_x)²

From which we see that T is a maximum when r_x = r0, i.e., for

the layer immediately next to the bore of the cylinder. Calling t0

the internal stress in this layer, and T0 the stress resulting from

the action inside the bore of the pressure P0, and allowing that the

sum of both these quantities must not exceed the elastic limit U of the

material, we have--T0 = U - t0. And for this value of T0, the

corresponding pressure inside the bore will be

R² - r0²

P = (U - t0) ----------.

R² + r0²

This pressure increases with the term (U - t0). With t0 positive,

i.e., when the internal stresses in the thickness of the hollow

cylinder are such that the metal of the layers nearest to the bore is

in a state of tension and that of the outer layers in a state of

compression, then the cylinder will have the least strength when t0

has the greatest numerical value. Such stresses are termed injurious

or detrimental stresses. With t0 negative, the strength of the

cylinder increases with the numerical value of t0, and those stresses

which cause compression in the layers nearest to the bore of the

cylinder and tension in the outer layers are termed beneficial or

useful stresses.

[Footnote 1: Lame holds that in a homogeneous tube subjected to

the action of two pressures, external and internal, the

difference between the tension and the compression developed at

any point of the thickness of the tube is a constant quantity,

and that the sum of these two stresses is inversely proportional

to the square of the radius of the layer under consideration. Let

r0, R, and r_x be the respective radii, p0, p¹, and p_x the

corresponding pressures, and T0, T¹, and T_x, the tensions, then

we have:

T0 - p0 = T_x - p_x (1)

(T0 + p0) r0² = (T_x + p_x) (r_x)² (2)

T_x - p_x = T¹ - p¹ (3)

(T_x + p_x)(r_x)² = (T¹ + P¹)R² (4)

if the radii are known and p and p¹ be given, then deducing from

the above equations the values T0 and T¹, and also the variable

pressure p_x, we determine--

p0 r0²(R² + (r_x)²) - p¹ R²((r_x)² + r0²)

T_x = ------------------------------------------

(R² + r0²) (r_x)²

This is the formula of Lame, from which, making p¹ = 0, we obtain

the expression in the text.]

For these reasons, and in order to increase the power of resistance of a

cylinder, it is necessary to obtain on the inner layer a state of

initial compression approaching as nearly as possible to the elastic

limit of the metal. This proposition is in reality no novelty, since it

forms the basis of the theory of hooped guns, by means of which the

useful initial stresses which should be imparted to the metal throughout

the gun can be calculated, and the extent to which the gun is thereby

strengthened determined. The stresses which arise in a hollow cylinder

when it is formed of several layers forced on one upon another, with a

definite amount of shrinkage, we call the stress of built-up cylinders,

in order to distinguish them from natural stresses developed in

homogeneous masses, and which vary in character according to the

conditions of treatment which the metal has undergone. If we conceive a

hollow cylinder made up of a great number of very thin layers--for

instance, of wire wound on with a definite tension--in which case the

inner layer would represent the bore of the gun, then the distribution

of the internal stresses and their magnitude would very nearly approach

the ideally perfect useful stresses which should exist in a homogeneous

cylinder; but in hollow cylinders built up of two, three, and four

layers of great thickness, there would be a considerable deviation from

the conditions which should be aimed at.

The magnitude of the stresses in built-up cylinders is determined by

calculation, on the presumption that initial stresses do not exist in

the respective layers of the tube and of the hoops which make up the

walls of the cylinder. Nevertheless, Rodman, as early as the year 1857,

first drew attention to the fact that when metal is cast and then

cooled, under certain conditions, internal stresses are necessarily

developed; and these considerations led him, in the manufacture of cast

iron guns, to cool the bore with water and to heat the outside of the

moulds after casting. Although Rodman's method was adopted everywhere,

yet up to the present time no experiments of importance have been made

with the view of investigating the internal stresses which he had drawn

attention to, and in the transition from cast iron to steel guns the

question has been persistently shelved, and has only very lately

attracted serious attention. With the aid of the accepted theory

relating to the internal stresses in the metal of hooped guns, we can

form a clear idea of the most advantageous character for them to assume

both in homogeneous and in built-up hollow cylinders. In proof of this,

we can adduce the labors of Colonels Pashkevitch and Duchene, the former

of whom published an account of his investigations in the _Artillery

Journal_ for 1884--St. Petersburg--and the latter in a work entitled

"Basis of the Theory of Hooped Guns," from which we borrow some of the

following information.

The maximum resistance of a tube or hollow cylinder to external stresses

will be attained when all the layers are expanded simultaneously to the

elastic limit of the material employed. In that case, observing the same

notation as that already adopted, we have--

R - r0

P0 = T -------- (1)

r0

But since the initial internal stresses before firing, that is previous

to the action of the pressure inside the bore, should not exceed the

elastic limit,[2] the value of R will depend upon this condition.

[Footnote 2: We must, however, remark that in a built-up hollow

cylinder the compression of the metal at the surface of the bore

may exceed the elastic limit. This cannot occur in the case of

natural stresses.]

In a hollow cylinder which in a state of rest is free from initial

stresses, the fiber of which, under fire, will undergo the maximum

extension, will be that nearest to the internal surface, and the amount

of extension of all the remaining layers will decrease with the increase

of the radius. This extension is thus represented--

(r0)² (r_x)² + R²

(t_x)¹ = P0 ------------ . ------------

R² - (r0)² (r_x)²

Therefore, to obtain the maximum resistance in the cylinder, the value

t_x of the initial stress will be determined by the difference (T - t'_x),[*need to check the prime with library or work out the equations]

and since P0 is given by Equation (1), then

/ r0 (r_x)² + R² \

t_x = T ( 1 - ---------- · ------------- ) (2)

\ R0 + r0 (r_x)² /

The greatest value t_x = t0 corresponds to the surface of the bore

and must be t0 = -T, therefore

r0² + R²

--------------- = 2

r0 (R + r0)

whence P0 = T sqrt(2) = 1.41 T.

From the whole of the preceding, it follows that in a homogeneous

cylinder under fire we can only attain simultaneous expansion of all the

layers when certain relations between the radii obtain, and on the

assumption that the maximum pressure admissible in the bore does not

exceed 1.41 U.

Scientific American Supplement, No. 633, February 18, 1888 · 第 9 / 49 题