L = R cos ½[phi] = (G/g) bt (v - u)² sin [phi].

[Illustration: FIG. 162.]

The work done by the jet on the vane is Pu = (G/g)btu(v - u)²(1 - cos

[phi]), which is a maximum when u = 1/3 v. This result can also be

obtained by considering that the work done on the plane must be equal

to the energy lost by the water, when friction is neglected.

If [phi] = 180°, cos [phi] = -1, 1 - cos [phi] = 2; then P =

2(G/g)bt(v - u)², the same result as for a concave cup.

[Illustration: FIG. 163.]

§ 161. _Position which a Movable Plane takes in Flowing Water._--When

a rectangular plane, movable about an axis parallel to one of its

sides, is placed in an indefinite current of fluid, it takes a

position such that the resultant of the normal pressures on the two

sides of the axis passes through the axis. If, therefore, planes

pivoted so that the ratio a/b (fig. 163) is varied are placed in

water, and the angle they make with the direction of the stream is

observed, the position of the resultant of the pressures on the plane

is determined for different angular positions. Experiments of this

kind have been made by Hagen. Some of his results are given in the

following table:--

+-----------+-------------+--------------+

| |Larger plane.|Smaller Plane.|

+-----------+-------------+--------------+

| a/b = 1.0 |[phi] = ... |[phi] = 90° |

| 0.9 | 75° | 72½° |

| 0.8 | 60° | 57° |

| 0.7 | 48° | 43° |

| 0.6 | 25° | 29° |

| 0.5 | 13° | 13° |

| 0.4 | 8° | 6½° |

| 0.3 | 6° | .. |

| 0.2 | 4° | .. |

+-----------+-------------+--------------+

§ 162. _Direct Action distinguished from Reaction_ (Rankine, _Steam

Engine_, § 147).

The pressure which a jet exerts on a vane can be distinguished into

two parts, viz.:--

(1) The pressure arising from changing the direct component of the

velocity of the water into the velocity of the vane. In fig. 153, §

154, ab cos bae is the direct component of the water's velocity, or

component in the direction of motion of vane. This is changed into the

velocity ae of the vane. The pressure due to direct impulse is then

P1 = GQ(ab cos bae - ae)/g.

For a flat vane moving normally, this direct action is the only action

producing pressure on the vane.

(2) The term reaction is applied to the additional action due to the

direction and velocity with which the water glances off the vane. It

is this which is diminished by the friction between the water and the

vane. In Case 2, § 160, the direct pressure is

P1 = Gbt(v - u)²/g.

Encyclopaedia Britannica, 11th Edition, "Husband" to "Hydrolysis" Volume 14, Slice 1 · 第 155 / 207 题