STANDING WAVES

§ 121. The formation of a standing wave was first observed by Bidone.

Into a small rectangular masonry channel, having a slope of 0.023 ft.

per foot, he admitted water till it flowed uniformly with a depth of

0.2 ft. He then placed a plank across the stream which raised the

level just above the obstruction to 0.95 ft. He found that the stream

above the obstruction was sensibly unaffected up to a point 15 ft.

from it. At that point the depth suddenly increased from 0.2 ft. to

0.56 ft. The velocity of the stream in the part unaffected by the

obstruction was 5.54 ft. per second. Above the point where the abrupt

change of depth occurred u² = 5.54² = 30.7, and gh = 32.2 × 0.2 =

6.44; hence u² was > gh. Just below the abrupt change of depth u =

5.54 × 0.2/0.56 = 1.97; u² = 3.88; and gh = 32.2 × 0.56 = 18.03; hence

at this point u² < gh. Between these two points, therefore, u² = gh;

and the condition for the production of a standing wave occurred.

[Illustration: FIG. 126.]

The change of level at a standing wave may be found thus. Let fig. 126

represent the longitudinal section of a stream and ab, cd cross

sections normal to the bed, which for the short distance considered

may be assumed horizontal. Suppose the mass of water abcd to come to

a´b´c´d´ in a short time t; and let u0, u1 be the velocities at ab and

cd, [Omega]0, [Omega]1 the areas of the cross sections. The force

causing change of momentum in the mass abcd estimated horizontally is

simply the difference of the pressures on ab and cd. Putting h0, h1

for the depths of the centres of gravity of ab and cd measured down

from the free water surface, the force is G(h0[Omega]0 - h1[Omega]1)

pounds, and the impulse in t seconds is G (h0[Omega]0 - h1[Omega]1) t

second pounds. The horizontal change of momentum is the difference of

the momenta of cdc´d´ and aba´b´; that is,

(G/g)([Omega]1u1² - [Omega]0u0²)t.

Hence, equating impulse and change of momentum,

G(h0[Omega]0 - h1[Omega]1)t = (G/g)([Omega]1u1² - [Omega]0u0²)t;

.: h0[Omega]0 - h1[Omega]1 = ([Omega]1u1² - [Omega]0u0²)/g. (1)

For simplicity let the section be rectangular, of breadth B and depths

H0 and H1, at the two cross sections considered; then h0 = ½H0, and h1

= ½H1. Hence

H0² - H1² = (2/g)(H1u1² - H0u0²).

Encyclopaedia Britannica, 11th Edition, "Husband" to "Hydrolysis" Volume 14, Slice 1 · 第 140 / 207 题