The above result may be obtained thus (fig. 116):--
[chi] = b + 2d/sin [beta]. (1)
[Omega] = d(b + d cot [beta]);
[Omega]/d = b + d cot [beta]; (2)
[Omega]/d² = b/d + cot [beta]. (3)
From (1) and (2),
[chi] = [Omega]/d - d cot [beta] + 2d/sin [beta].
Encyclopaedia Britannica, 11th Edition, "Husband" to "Hydrolysis" Volume 14, Slice 1 · 第 132 / 207 题