Q = (2/3)cb [root](2g) {(h2 + [h])^(3/2) - [h]^(3/2)}. (2)

In cases where u can be directly determined, these formulae give the

discharge quite simply. When, however, u is only known as a function

of the section of the stream in the channel of approach, they become

complicated. Let [Omega] be the sectional area of the channel where h1

and h2 are measured. Then u = Q/[Omega] and [h] = Q²/2g [Omega]².

This value introduced in the equations above would render them

excessively cumbrous. In cases therefore where [Omega] only is known,

it is best to proceed by approximation. Calculate an approximate value

Q´ of Q by the equation

Q´ = (2/3)cb [root](2g) {h2^(3/2) - h1^(3/2)}.

Then [h] = Q´²/2g[Omega]² nearly. This value of [h] introduced in the

equations above will give a second and much more approximate value of

Q.

[Illustration: FIG. 49.]

§ 46. _Partially Submerged Rectangular Orifices and Notches._--When

the tail water is above the lower but below the upper edge of the

orifice, the flow in the two parts of the orifice, into which it is

divided by the surface of the tail water, takes place under different

conditions. A filament M1m1 (fig. 49) in the upper part of the orifice

issues with a head h´ which may have any value between h1 and h. But a

filament M2m2 issuing in the lower part of the orifice has a velocity

due to h´´ - h´´´, or h, simply. In the upper part of the orifice the

head is variable, in the lower constant. If Q1, Q2 are the discharges

from the upper and lower parts of the orifice, b the width of the

orifice, then

Q1 = (2/3)cb [root](2g) {h^(3/2) - h1^(3/2)}

(3)

Q1 = cb (h2 - h) [root](2gh).

In the case of a rectangular notch or weir, h1 = 0. Inserting this

value, and adding the two portions of the discharge together, we get

for a drowned weir

Encyclopaedia Britannica, 11th Edition, "Husband" to "Hydrolysis" Volume 14, Slice 1 · 第 68 / 207 题