G0 = 1/V0 = 2116.8/26214 = .08075. (2)

For any other pressure p, at which the volume of 1 lb. is V and the

weight per cubic foot is G, the temperature being 32° Fahr.,

pV = p/G = 26214; or G = p/26214. (3)

_Change of Pressure or Volume by Change of Temperature._--Let p0, V0,

G0, as before be the pressure, the volume of a pound in cubic feet,

and the weight of a cubic foot in pounds, at 32° Fahr. Let p, V, G be

the same quantities at a temperature t (measured strictly by the air

thermometer, the degrees of which differ a little from those of a

mercurial thermometer). Then, by experiment,

pV = p0V0(460.6 + t)/(460.6 + 32) = p0V0[tau]/[tau]0, (4)

where [tau], [tau]0 are the temperatures t and 32° reckoned from the

absolute zero, which is -460.6° Fahr.;

p/G = p0[tau]/G0[tau]0; (4a)

Encyclopaedia Britannica, 11th Edition, "Husband" to "Hydrolysis" Volume 14, Slice 1 · 第 31 / 207 题