Axᵖy𐞥 + A(ᵖ⁄ᵩ₊₁)xᵖ⁻¹y𐞥⁺¹ + A(ᵖ⁄ᵩ₊₁)(ᵖ⁻¹⁄ᵩ₊₂)xᵖ⁻²y𐞥⁺²

Now, when _(x+y)ᴹ_ is multiplied by _x+y_ to give _(x+y)ᴹ⁺¹_, we multiply

first by _x_ and then by _y_ instead of by _x_ and add the two results.

When we multiply by _x_, the second of the above three terms will be the

only one giving a term involving _xᵖy𐞥⁺¹_ and the third will be the only

one giving a term in _xᵖ⁻¹y𐞥⁺²_; and when we multiply by _y_ the first

will be the only term giving a term in _xᵖy𐞥⁺¹_, and the second will be

the only term giving a term in _xᵖ⁻¹y𐞥⁺²_. Hence, adding like terms,

we find that the coefficient of _xᵖy𐞥⁺¹_in the expansion of _(x+y)ᴹ⁺¹_

will be the sum of the coefficients of the first two of the above three

terms, and that the coefficient of _xᵖ⁻¹y𐞥⁺²_ will be the sum of the

coefficients of the last two terms. Hence, two successive terms in the

expansion of _(x+y)ᴹ⁺¹_ will be

The Monist, Vol. 2, 1891-1892 · 第 307 / 390 题