QUARTER-SPACE LANDING, WREATH IN TWO PIECES.

It was said in a previous case that with a wide rail and the tangents

on the same pitch as the straight rail, the inside of rail has a

crippled appearance. This can be remedied by having the wreath in two

pieces.

Fig. 1 shows the plan laid down so as to make the inside falling line

of rail a straight line; and the risers landing and starting placed in

the springing. To find the radius of centre line of rail, Fig. 1. Make

S N, Fig. 7, equal one step. From N draw N R at 45° with S N, and from

S draw a line at 60° with S N to meet the line from N in R, from R draw

square to and cut S N in P; then R P will be the radius for the inside

of the rail on plan.

Fig. 2 shows the development. Make H R equal stretch-out of centre line

of rail on plan. Set up one tread and risers above and below, with the

risers in the springing. Draw the centre falling line, resting on the

corners and passing through the centre, at the height of half a riser

above the landing. To develop tangents, make C S R Fig. 2, equal C B A,

Fig. 1, and complete tangents as shown. To draw the horizontal trace

at Fig. 1, make A B F, Fig. 1, equal R S F, Fig. 2. Join F C for the

required trace. Draw N O square to it.

Fig. 3 shows the face mould. Make A B F equal A B F and B C equal B C,

Fig. 2, and F C equal F C, Fig. 1. Make C P equal C N, Fig. 1. Draw the

major axis from N square to N C F. Draw from A parallel to F C P to

cut major axis in 7. Now if the drawing is correct A 7 will equal A R,

Fig. 1. With P as centre and N R, Fig. 1, as radius, strike an arc at

S; again, with 7 as centre and A R, Fig. 2, as radius, strike an arc

to intersect the first one in S. Join 7 S and P S extended, and P N

equal O N, Fig. 1. Draw from N parallel to 7 S to cut the major axis in

O, then O will be the centre.

Fig. 4 shows the sections and bevels. Make N N equal radius of centre

line of rail, Fig. 1, with O as centre, and for radius just touching

each tangent, which distances transfer to Fig. 4. All the sections in

this case will be in the centre of the plank.

Fig. 5 shows the face mould for the other side of the plank.

Fig. 6 shows the application of the face moulds to the stuff.

Both joints are square to tangents and face of plank in this case.

[Illustration: PLATE 25.]

Practical Stair Building and Handrailing By the square section and falling line system. · 第 66 / 78 题