WINDERS IN THE HALF-SPACE AND LEVEL LANDING AT TOP.

Fig. 1 shows the plan with the centre line enclosed with tangents.

Having laid down the risers on plan, keeping the narrow ends of winders

as near as possible half a step, then with one baluster on each they

will be the same distance apart as on the square steps which have two.

This is not intended as a fixed rule but merely as a guide. The risers

must be placed so as to get a good falling line, and this can only be

ascertained by developing or unfolding the centre line and tangents on

a board.

Fig. 2 shows the development of centre line and tangents. Set up all

the treads and risers as they occur on the centre line of rail, Fig. 1.

Draw the springing through A and E. Draw the centre falling line

resting on the corners of square step at bottom and 4 inches above the

landing at top. It is better for the falling line to be a little higher

over the winders, especially near the top. To develop the tangents make

the distance between the lines 1 2 3 D E equal A B C D E, Fig. 1. Draw

D E level. From the centre joint on the falling line square out a line

to cut the line 3 at C, join D C extended to cut the line 2 in B. From

where the falling line cut the lower springing, square out a line to

cut the line 1 in A; join A B; then A B C will be the tangents for the

lower wreath and C D E for the top. Decide where the joint is to be

below the springing, and draw a line parallel to the tangent A B, and

tangent to the curve of the falling line where the joint is to be. The

joint must be square to this line. It will be necessary to have a ramp

here to ease into the straight rail, this is shown by the dotted lines.

In the next plate is shown a method of easing the wreath into the

straight rail without the aid of a ramp.

Fig. 3 shows the bottom face mould. Make C B F and B A equal C B A

and B A, Fig. 2, and F A equal F A, Fig. 1, and complete the mould as

usual. To find what each section is out of the centre of the plank,

make W 4 5, Fig. 2, equal C 4 5 on the centre line of rail, Fig. 1;

make 4 4 and 5 5, Fig. 2, equal N O and N H, Fig. 3. The difference

between the falling line and 4 is what the section 4 on the minor axis

is above the centre; and that between 5 and the falling line is what

the section 5 is out of the centre. The section at both joints is in

the centre, but at the springing A the falling line is a little above

the centre, as it cut the springing above the level line A W, which

is the height of the centre of the plank there. Get out the mould for

the opposite side of the plank in the usual way, by laying Fig. 3 on a

thin piece of stuff, and transfer the tangents and section lines on to

it. Stick a bradawl through A 5 4 C and mark off out to it A 7 5 8 and

5 9, and C 10 and C 11, only on the opposite side. Work the inside and

outside off first with a gig-saw, as before described. The shaded parts

of sections at Fig. 4 show the superfluous stuff there is to come off

the top side.

Fig. 5 shows the face mould for the top half. Draw C D E at right

angles, and to equal C D E, Fig. 2. To see what the sections are out

of the centre, make E 3 2, Fig. 2, equal E 3 2 on centre line of rail,

Fig. 1. Make 2 2 and 3 3, Fig. 2, equal S R and S L. The difference

between 2 and the falling line is what the section 2 is below the

centre of plank, and that between 3 and the falling line is what the

section 3 is below the centre. And that between E and the falling line

is what it is below there.

Fig. 6 shows the sections, and the shaded part shows the superfluous

stuff there is to come off the top at each section, after the inside

and outside have been cut off.

Fig. 7 shows the wreath after the inside and outside have been cut off;

the dotted lines show the wreath cut square through the plank.

[Illustration: PLATE 22.]

Practical Stair Building and Handrailing By the square section and falling line system. · 第 60 / 78 题