Cast Iron, a = T/25000

As this pamphlet has to do with wooden bridges only, nothing will be

said of the proper relative dimensions of cast-iron columns to sustain

the strains to which they may be subjected, but a table of the

strength of columns will be found further on.

=Transverse Strains.=

Let W = breaking weight in lbs.

" s = constant in table.

" b = breadth in inches.

" d = depth in inches.

" L = length in inches.

Then, for the power of a beam to resist a transverse strain, we shall

have,

4 sbd²

W = ------

L

[TeX: $W = \frac{4 sbd^2}{L}$]

This formula has been derived from experiments made by the most

reliable authorities.

The constant, 1250, adopted for wood in the following formula, is an

average constant, derived from the table, of those woods more commonly

used.

Now to reduce the formula to the most convenient shape for use, we

substitute the value of s, and we have

4 x 1250 bd²

W = ------------,

L

[TeX: $W = \frac{4 \times 1250 bd^2}{L}$]

or

5000 bd²

W = --------.

L

[TeX: $W = \frac{5000 bd^2}{L}$]

But, to reduce the load to the proper working strain, we must divide

this equivalent by 4, the factor of safety, and we shall have

5000 bd²

W = --------.

4L

[TeX: $W = \frac{5000 bd^2}{4 L}$]

Instructions on Modern American Bridge Building · 第 23 / 46 题