TO FIND THE AZIMUTH OF POLARIS.

As we have shown the azimuth of Polaris to be a function of the

latitude, and as the latitude is now known, we may proceed to find the

required azimuth. For this purpose we have a right-angled spherical

triangle, Z S P, Fig. 4, in which Z is the place of observation, P the

north pole, and S is Polaris. In this triangle we have given the polar

distance, P S = 10° 19' 13"; the angle at S = 90°; and the distance Z

P, being the complement of the latitude as found above, or 90°--L.

Substituting these in the formula for the azimuth, we will have sin. Z =

sin. P S / sin P Z or sin. of Polar distance / sin. of co-latitude, from

which, by assuming different values for the co-latitude, we compute the

following table:

AZIMUTH TABLE FOR POINTS BETWEEN 26° and 50° N. LAT.

LATTITUDES

___________________________________________________________________

| | | | | | | |

| Year | 26° | 28° | 30° | 32° | 34° | 36° |

|______|_________|__________|_________|_________|_________|_________|

| | | | | | | |

| | ° ' " | ° ' " | ° ' " | ° ' " | ° ' " | ° ' " |

| 1882 | 1 28 05 | 1 29 40 | 1 31 25 | 1 33 22 | 1 35 30 | 1 37 52 |

| 1883 | 1 27 45 | 1 29 20 | 1 31 04 | 1 33 00 | 1 35 08 | 1 37 30 |

| 1884 | 1 27 23 | 1 28 57 | 1 30 41 | 1 32 37 | 1 34 45 | 1 37 05 |

| 1885 | 1 27 01 | 1 28 35½ | 1 30 19 | 1 32 14 | 1 34 22 | 1 36 41 |

| 1886 | 1 26 39 | 1 28 13 | 1 29 56 | 1 31 51 | 1 33 57 | 1 36 17 |

|______|_________|__________|_________|_________|_________|_________|

| | | | | | | |

| Year | 38° | 40° | 42° | 44° | 46° | 48° |

|______|_________|__________|_________|_________|_________|_________|

| | | | | | | |

| | ° ' " | ° ' " | ° ' " | ° ' " | ° ' " | ° ' " |

| 1882 | 1 40 29 | 1 43 21 | 1 46 33 | 1 50 05 | 1 53 59 | 1 58 20 |

| 1883 | 1 40 07 | 1 42 58 | 1 46 08 | 1 49 39 | 1 53 34 | 1 57 53 |

| 1884 | 1 39 40 | 1 42 31 | 1 45 41 | 1 49 11 | 1 53 05 | 1 57 23 |

| 1885 | 1 39 16 | 1 42 07 | 1 45 16 | 1 48 45 | 1 52 37 | 1 56 54 |

| 1886 | 1 38 51 | 1 41 41 | 1 44 49 | 1 48 17 | 1 52 09 | 1 56 24 |

|______|_________|__________|_________|_________|_________|_________|

| | |

| Year | 50° |

|______|_________|

| | |

| | ° ' " |

| 1882 | 2 03 11 |

| 1883 | 2 02 42 |

| 1884 | 2 02 11 |

| 1885 | 2 01 42 |

| 1886 | 2 01 11 |

|______|_________|

An analysis of this table shows that the azimuth this year (1882)

increases with the latitude from 1° 28' 05" at 26° north, to 2° 3' 11"

at 50° north, or 35' 06". It also shows that the azimuth of Polaris at

any one point of observation decreases slightly from year to year. This

is due to the increase in declination, or decrease in the star's polar

distance. At 26° north latitude, this annual decrease in the azimuth

is about 22", while at 50° north, it is about 30". As the variation in

azimuth for each degree of latitude is small, the table is only computed

for the even numbered degrees; the intermediate values being readily

obtained by interpolation. We see also that an error of a few minutes of

latitude will not affect the result in finding the meridian, e.g., the

azimuth at 40° north latitude is 1° 43' 21", that at 41° would be 1° 44'

56", the difference (01' 35") being the correction for one degree of

latitude between 40° and 41°. Or, in other words, an error of one degree

in finding one's latitude would only introduce an error in the azimuth

of one and a half minutes. With ordinary care the probable error of the

latitude as determined from the method already described need not exceed

a few minutes, making the error in azimuth as laid off on the arc of an

ordinary transit graduated to single minutes, practically zero.

REFRACTION TABLE FOR ANY ALTITUDE WITHIN THE LATITUDE OF THE UNITED

STATES.

_____________________________________________________

| | | | |

| Apparent | Refraction | Apparent | Refraction |

| Altitude. | _minus_. | Altitude. | _minus_. |

|___________|______________|___________|______________|

| | | | |

| 25° | 0° 2' 4.2" | 38° | 0° 1' 14.4" |

| 26 | 1 58.8 | 39 | 1 11.8 |

| 27 | 1 53.8 | 40 | 1 9.3 |

| 28 | 1 49.1 | 41 | 1 6.9 |

| 29 | 1 44.7 | 42 | 1 4.6 |

| 30 | 1 40.5 | 43 | 1 2.4 |

| 31 | 1 36.6 | 44 | 0 0.3 |

| 32 | 1 33.0 | 45 | 0 58.1 |

| 33 | 1 29.5 | 46 | 0 56.1 |

| 34 | 1 26.1 | 47 | 0 54.2 |

| 35 | 1 23.0 | 48 | 0 52.3 |

| 36 | 1 20.0 | 49 | 0 50.5 |

| 37 | 1 17.1 | 50 | 0 48.8 |

|___________|______________|___________|______________|

Scientific American Supplement, No. 360, November 25, 1882 · 第 47 / 60 题