N = (N + D) e^{-λt}

and solve

t = 1/λ · ln(1 + D/N)

where ln = the natural logarithm, the logarithm to base e.

This kind of system can be represented crudely by an old-fashioned

hourglass, as shown in the figure, which has the parameters of these

equations marked. (Keep in mind, however, that this is only a gross

analogy. Nuclear clocks run at logarithmically decreasing rates, but the

speed of a good hourglass is roughly constant.)

[Illustration: _An hourglass illustrates an ideal closed system. Nothing

is added and nothing is removed—the sand just runs from the top bulb to

the bottom._]

Remember that the decaying nucleus does not disappear. It changes into

another nucleus, and this new nucleus forms an atom that may be captured

and held fixed by natural processes. The decayed nuclei are thus

collected, so that here we have the bottom chamber of the hourglass.

But sometimes we need only the top chamber of an hourglass.

Nuclear Clocks Revised · 第 10 / 47 题