428.--THE GARDENER AND THE COOK.

Nobody succeeded in solving the puzzle, so I had to let the cat out of

the bag--an operation that was dimly foreshadowed by the puss in the

original illustration. But I first reminded the reader that this puzzle

appeared on April 1, a day on which none of us ever resents being made

an "April Fool;" though, as I practically "gave the thing away" by

specially drawing attention to the fact that it was All Fools' Day, it

was quite remarkable that my correspondents, without a single exception,

fell into the trap.

One large body of correspondents held that what the cook loses in stride

is exactly made up in greater speed; consequently both advance at the

same rate, and the result must be a tie. But another considerable

section saw that, though this might be so in a race 200 ft. straight

away, it could not really be, because they each go a stated distance at

"every bound," and as 100 is not an exact multiple of 3, the gardener at

his thirty-fourth bound will go 2 ft. beyond the mark. The gardener

will, therefore, run to a point 102 ft. straight away and return (204

ft. in all), and so lose by 4 ft. This point certainly comes into the

puzzle. But the most important fact of all is this, that it so happens

that the gardener was a pupil from the Horticultural College for Lady

Gardeners at, if I remember aright, Swanley; while the cook was a very

accomplished French chef of the hemale persuasion! Therefore "she (the

gardener) made three bounds to his (the cook's) two." It will now be

found that while the gardener is running her 204 ft. in 68 bounds of 3

ft., the somewhat infirm old cook can only make 45+1/3 of his 2 ft.

bounds, which equals 90 ft. 8 in. The result is that the lady gardener

wins the race by 109 ft. 4 in. at a moment when the cook is in the air,

one-third through his 46th bound.

The moral of this puzzle is twofold: (1) Never take things for granted

in attempting to solve puzzles; (2) always remember All Fools' Day when

it comes round. I was not writing of _any_ gardener and cook, but of a

_particular_ couple, in "a race that I witnessed." The statement of the

eye-witness must therefore be accepted: as the reader was not there, he

cannot contradict it. Of course the information supplied was

insufficient, but the correct reply was: "Assuming the gardener to be

the 'he,' the cook wins by 4 ft.; but if the gardener is the 'she,' then

the gardener wins by 109 ft. 4 in." This would have won the prize.

Curiously enough, one solitary competitor got on to the right track, but

failed to follow it up. He said: "Is this a regular April 1 catch,

meaning that they only ran 6 ft. each, and consequently the race was

unfinished? If not, I think the following must be the solution,

supposing the gardener to be the 'he' and the cook the 'she.'" Though

his solution was wrong even in the case he supposed, yet he was the only

person who suspected the question of sex.

Amusements in Mathematics · 第 964 / 970 题