Here is my solution for 9 persons on 28 occasions:--

2 1 9 7 4 5 6 3 8

2 9 5 1 6 8 3 4 7

2 9 3 1 8 4 7 5 6

2 9 1 5 6 4 7 8 3

There are here two repeaters, 1 and 2, and the cycle is 3, 4, 5, 6, 7,

8, 9. We thus get 4 groups of 7 lines each.

Amusements in Mathematics · 第 792 / 970 题