253.--A BANK HOLIDAY PUZZLE.

The simplest way is to write in the number of routes to all the towns in

this manner. Put a 1 on all the towns in the top row and in the first

column. Then the number of routes to any town will be the sum of the

routes to the town immediately above and to the town immediately to the

left. Thus the routes in the second row will be 1, 2, 3, 4, 5, 6, etc.,

in the third row, 1, 3, 6, 10, 15, 21, etc.; and so on with the other

rows. It will then be seen that the only town to which there are exactly

1,365 different routes is the twelfth town in the fifth row--the one

immediately over the letter E. This town was therefore the cyclist's

destination.

The general formula for the number of routes from one corner to the

corner diagonally opposite on any such rectangular reticulated

arrangement, under the conditions as to direction, is (m+n)!/m!n!,

where m is the number of towns on one side, less one, and n the number

on the other side, less one. Our solution involves the case where

there are 12 towns by 5. Therefore m = 11 and n = 4. Then the formula

gives us the answer 1,365 as above.

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