128.--A PROBLEM IN SQUARES.

The sides of the three boards measure 31 in., 41 in., and 49 in. The

common difference of area is exactly five square feet. Three numbers

whose squares are in A.P., with a common difference of 7, are 113/120,

337/120, 463/120; and with a common difference of 13 are 80929/19380,

106921/19380, and 127729/19380. In the case of whole square numbers the

common difference will always be divisible by 24, so it is obvious that

our squares must be fractional. Readers should now try to solve the case

where the common difference is 23. It is rather a hard nut.

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