117.--A FENCE PROBLEM.

Though this puzzle presents no great difficulty to any one possessing a

knowledge of algebra, it has perhaps rather interesting features.

Seeing, as one does in the illustration, just one corner of the proposed

square, one is scarcely prepared for the fact that the field, in order

to comply with the conditions, must contain exactly 501,760 acres, the

fence requiring the same number of rails. Yet this is the correct

answer, and the only answer, and if that gentleman in Iowa carries out

his intention, his field will be twenty-eight miles long on each side,

and a little larger than the county of Westmorland. I am not aware that

any limit has ever been fixed to the size of a "field," though they do

not run so large as this in Great Britain. Still, out in Iowa, where my

correspondent resides, they do these things on a very big scale. I have,

however, reason to believe that when he finds the sort of task he has

set himself, he will decide to abandon it; for if that cow decides to

roam to fresh woods and pastures new, the milkmaid may have to start out

a week in advance in order to obtain the morning's milk.

Here is a little rule that will always apply where the length of the

rail is half a pole. Multiply the number of rails in a hurdle by four,

and the result is the exact number of miles in the side of a square

field containing the same number of acres as there are rails in the

complete fence. Thus, with a one-rail fence the field is four miles

square; a two-rail fence gives eight miles square; a three-rail fence,

twelve miles square; and so on, until we find that a seven-rail fence

multiplied by four gives a field of twenty-eight miles square. In the

case of our present problem, if the field be made smaller, then the

number of rails will exceed the number of acres; while if the field be

made larger, the number of rails will be less than the acres of the

field.

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