6 . . . [Delta]y = 3x[Delta]s/4y.

From these equations the deflection produced by any given stress on the

chains or by a change of temperature can be calculated.

[Illustration: FIG. 71.]

36. _Deflection of Girders._-- Let fig. 71 represent a beam bent by

external loads. Let the origin O be taken at the lowest point of the bent

beam. Then the deviation y = DE of the neutral axis of the bent beam at any

point D from the axis OX is given by the relation

d²y M

--- = -- ,

dx² EI

where M is the bending moment and I the amount of inertia of the beam at D,

and E is the coefficient of elasticity. It is usually accurate enough in

deflection calculations to take for I the moment of inertia at the centre

of the beam and to consider it constant for the length of the beam. Then

dy 1

-- = ---[Integral]Mdx

dx EI

1

y = ---[Integral][Integral]Mdx².

EI

The integration can be performed when M is expressed in terms of x. Thus

for a beam supported at the ends and loaded with w per inch length M =

w(a²-x²), where a is the half span. Then the deflection at the centre is

the value of y for x = a, and is

5 wa^4

[delta] = --- ----.

24 EI

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