1 . . . H = wL²/8y,

or, calling x the distance from the vertex to the point of support,

H = wx²/2y,

The value of H is equal to the maximum tension on the bottom flange, or

compression on the top flange, of a girder of equal span, equally and

similarly loaded, and having a depth equal to the dip of the suspension

bridge.

[Illustration: FIG. 70.]

Consider any other point F of the curve, fig. 70, at a distance x [v.04

p.0556] from the vertex, the horizontal component of the resultant (tangent

to the curve) will be unaltered; the vertical component V will be simply

the sum of the loads between O and F, or wx. In the triangle FDC, let FD be

tangent to the curve, FC vertical, and DC horizontal; these three sides

will necessarily be proportional respectively to the resultant tension

along the chain at F, the vertical force V passing through the point D, and

the horizontal tension at O; hence

H : V = DC : FC = wx²/2y : wx = x/2 : y,

hence DC is the half of OC, proving the curve to be a parabola.

The value of R, the tension at any point at a distance x from the vertex,

is obtained from the equation

R² = H²+V² = w²x^4/4y²+w²x²,

or,

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