The only set of three numbers, of two, three, and five figures
respectively, that will fulfil the required conditions is 27 x 594 =
16,038. These three numbers contain all the nine digits and 0, without
repetition; the first two numbers multiplied together make the third, and
the second is exactly twenty-two times the first. If the numbers might
contain one, four, and five figures respectively, there would be many
correct answers, such as 3 x 5,694 = 17,082; but it is a curious fact
that there is only one answer to the problem as propounded, though it is
no easy matter to prove that this is the case.