75.--_The Spider and the Fly._

Though this problem was much discussed in the _Daily Mail_ from 18th

January to 7th February 1905, when it appeared to create great public

interest, it was actually first propounded by me in the _Weekly Dispatch_

of 14th June 1903.

Imagine the room to be a cardboard box. Then the box may be cut in

various different ways, so that the cardboard may be laid flat on the

table. I show four of these ways, and indicate in every case the relative

positions of the spider and the fly, and the straightened course which

the spider must take without going off the cardboard. These are the four

most favourable cases, and it will be found that the shortest route is in

No. 4, for it is only 40 feet in length (add the square of 32 to the

square of 24 and extract the square root). It will be seen that the

spider actually passes along five of the six sides of the room! Having

marked the route, fold the box up (removing the side the spider does not

use), and the appearance of the shortest course is rather surprising. If

the spider had taken what most persons will consider obviously the

shortest route (that shown in No. 1), he would have gone 42 feet! Route

No. 2 is 43.174 feet in length, and Route No. 3 is 40.718 feet.

[Illustration]

I will leave the reader to discover which are the shortest routes when

the spider and the fly are 2, 3, 4, 5, and 6 feet from the ceiling and

the floor respectively.

The Canterbury Puzzles, and Other Curious Problems · 第 241 / 286 题