45.--_The Riddle of the Cellarer._

There were 100 pints of wine in the cask, and on thirty occasions John

the Cellarer had stolen a pint and replaced it with a pint of water.

After the first theft the wine left in the cask would be 99 pints; after

the second theft the wine in the cask would be 9801/100 pints (the square

of 99 divided by 100); after the third theft there would remain

970299/10000 (the cube of 99 divided by the square of 100); after the

fourth theft there would remain the fourth power of 99 divided by the

cube of 100; and after the thirtieth theft there would remain in the cask

the thirtieth power of 99 divided by the twenty-ninth power of 100. This

by the ordinary method of calculation gives us a number composed of 59

figures to be divided by a number composed of 58 figures! But by the use

of logarithms it may be quickly ascertained that the required quantity is

very nearly 73-97/100 pints of wine left in the cask. Consequently the

cellarer stole nearly 26.03 pints. The monks doubtless omitted the answer

for the reason that they had no tables of logarithms, and did not care to

face the task of making that long and tedious calculation in order to get

the quantity "to a nicety," as the wily cellarer had stipulated.

By a simplified process of calculation, I have ascertained that the exact

quantity of wine stolen would be

26.0299626611719577269984907683285057747323737647323555652999

pints. A man who would involve the monastery in a fraction of fifty-eight

decimals deserved severe punishment.

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