38.--_The Amulet._

The puzzle was to place your pencil on the A at the top of the amulet and

count in how many different ways you could trace out the word

"Abracadabra" downwards, always passing from a letter to an adjoining

one.

A

B B

R R R

A A A A

C C C C C

A A A A A A

D D D D D D D

A A A A A A A A

B B B B B B B B B

R R R R R R R R R R

A A A A A A A A A A A

"Now, mark ye, fine fellows," said Sir Hugh to some who had besought him

to explain, "that at the very first start there be two ways open:

whichever B ye select, there will be two several ways of proceeding

(twice times two are four); whichever R ye select, there be two ways of

going on (twice times four are eight); and so on until the end. Each

letter in order from A downwards may so be reached in 2, 4, 8, 16, 32,

etc., ways. Therefore, as there be ten lines or steps in all from A to

the bottom, all ye need do is to multiply ten 2's together, and truly the

result, 1024, is the answer thou dost seek."

The Canterbury Puzzles, and Other Curious Problems · 第 194 / 286 题