From equations (1) and (2) we have

1 / I k2 dX \

n1e = ------- ( - + ----- -- ) (3),

k1 + k2 \ X 4[pi] dx /

1 / I k1 dX \

n2e = ------- ( - - ----- -- ) (4),

k1 + k2 \ X 4[pi] dx /

and from these equations we can, if we know the distribution of

electric intensity between the plates, calculate the number of

positive and negative ions.

In a steady state the number of positive and negative ions in unit

volume at a given place remains constant, hence neglecting the loss by

diffusion, we have

d

--(k1n1X) = q - [alpha]n1n2 (5).

dx

d

- --(k2n2X) = q - [alpha]n1n2 (6).

dx

Encyclopaedia Britannica, 11th Edition, "Conduction, Electric" Volume 6, Slice 8 · 第 13 / 28 题