The radius of curvature of the meridian section is
ds
R1 = - -------- (12).
d[alpha]
The radius of curvature of a normal section of the surface at right
angles to the meridian section is equal to the part of the normal cut
off by the axis, which is
R2 = PN = y/cos[alpha] (13).
Encyclopaedia Britannica, 11th Edition, "Capefigue" to "Carneades" Volume 5, Slice 3 · 第 50 / 74 题