The radius of curvature of the meridian section is

ds

R1 = - -------- (12).

d[alpha]

The radius of curvature of a normal section of the surface at right

angles to the meridian section is equal to the part of the normal cut

off by the axis, which is

R2 = PN = y/cos[alpha] (13).

Encyclopaedia Britannica, 11th Edition, "Capefigue" to "Carneades" Volume 5, Slice 3 · 第 50 / 74 题